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PNP spectrochemistry Prelab assignment, Spring 2010 Page 1 PNP ...

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<strong>PNP</strong> prelab <strong>assignment</strong>, <strong>PNP</strong> spectroscopy lab. Name ____________________<br />

Lab day___________________<br />

1. Using only stock solutions of 0.1 M KH2PO4 and 0.1 M K2HPO4 you wish to prepare 5.0 mL solutions<br />

of potassium phosphate buffers with pH values of 6.5, 7.2 and 7.6. Noting that the pKa of KH2PO4 to<br />

K2HPO4 is 6.82, use the Henderson‐Hasselbalch equation to calculate the relative amounts of the<br />

two stocks needed to generate these pH values. Show your work in the space below the table to<br />

get full credit.<br />

Hndsn/Hssblch<br />

predicted pH<br />

6.5<br />

7.2<br />

7.6<br />

Calculated ratio<br />

Volume of<br />

0.1 M KH2PO4<br />

(mL)<br />

Volume of<br />

0.1 M K2HPO4<br />

(mL)<br />

Total Volume<br />

(mL)<br />

0.47863 3.4 1.6 5<br />

2.399 1.5 3.5 5<br />

6.025 0.7 4.3 5<br />

Note that this question is similar to the table you must complete in the <strong>PNP</strong> protocol. You should<br />

copy your answers from this <strong>assignment</strong> into that table!<br />

2. Using a 0.1 mM <strong>PNP</strong> solution and pH 10 buffer for dilution, prepare a series of 2 mL standards with<br />

final concentrations of <strong>PNP</strong> of 2, 4, 6, 10, 15, and 25 μM.<br />

Sample<br />

Name<br />

Std. 1<br />

Std. 2<br />

Std. 3<br />

Std. 4<br />

Std. 5<br />

Std. 6<br />

Vol. of 0.1 mM<br />

(100 μM) <strong>PNP</strong><br />

(μL)<br />

Vol. of pH<br />

10 buffer<br />

(μL)<br />

Total<br />

Volume<br />

(μL)<br />

Final<br />

Conc. of<br />

<strong>PNP</strong><br />

(μM)<br />

40 1960 2000 2<br />

80 1920 2000 4<br />

120 1880 2000 6<br />

200 1800 2000 10<br />

300 1700 2000 15<br />

500 1500 2000 25<br />

Note that this question is similar to the table you must complete in the <strong>PNP</strong> protocol. You should<br />

copy your answers from this <strong>assignment</strong> into that table!<br />

<strong>PNP</strong> <strong>spectrochemistry</strong> <strong>Prelab</strong> <strong>assignment</strong>, <strong>Spring</strong> <strong>2010</strong> <strong>Page</strong> 1


Sample calculation for problem 1<br />

For pH 6.5:<br />

<br />

<br />

6.5 6.82 <br />

<br />

0.32 <br />

<br />

0.47863 <br />

<br />

We have 2 variables, and 2 equations:<br />

Equation 1: Equation 2:<br />

A‐+HA = 5 mL A‐/HA = ratio (in this case 0.47863)<br />

Start:<br />

A‐/HA=0.47863<br />

A‐=0.47863HA<br />

Plug this into equation 1<br />

0.47863HA + HA = 5<br />

1.47863HA =5<br />

HA = 3.4<br />

Plug this into Equation 1:<br />

A‐+3.4 = 5.0<br />

A‐ = 1.6<br />

For problem 2, use M1V1 = M2V2 where M1=100 uM, M2=value in column 5, and V2=2000 uL. Solve for<br />

V1. Volume of pH 10 buffer is simply 2000 uL – V1.<br />

<strong>PNP</strong> <strong>spectrochemistry</strong> <strong>Prelab</strong> <strong>assignment</strong>, <strong>Spring</strong> <strong>2010</strong> <strong>Page</strong> 2

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