Chapter 10 Torsion Tests
Chapter 10 Torsion Tests
Chapter 10 Torsion Tests
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Shear stress<br />
• The maximum shear stress at the surface of the bar is<br />
M T D / 2 16M<br />
T<br />
4<br />
3<br />
τ max = =<br />
πD<br />
/ 32<br />
πD<br />
• For a tubular specimen, the shear stress on the outer surface is<br />
16<br />
τ =<br />
π ( D<br />
M T<br />
4<br />
1<br />
Where D 1 = Outside diameter of tube<br />
D 2 = Inside diameter of tube<br />
−<br />
D<br />
D<br />
Suranaree University of Technology May-Aug 2007<br />
1<br />
4<br />
2<br />
)<br />
Eq.4<br />
Eq.5<br />
Note: Eq.4 and Eq.5 is applied only for a linear relationship.<br />
Tapany Udomphol
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