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FIVE MAJOR RESULTS IN ANALYSIS AND TOPOLOGY Aaron ...

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3. THE STONE-WEIERSTRASS THEOREM 17<br />

The Weierstrass approximation theorem allows us to choose a sequence of polynomials<br />

which converge uniformly to a given continuous function f. Since the pointwise limit of a<br />

uniformly convergent sequence of functions has many of the same properties as the terms in<br />

the sequence, this theorem tells us a great deal about C([a,b], C).<br />

There is a significant generalization of Weierstrass’ approximation theorem due to Mar-<br />

shall Stone, which relaxes two of the conditions of Weierstrass’ theorem. First, set of func-<br />

tions is not required to be polynomials, but rather a type of subclass A of C(K, C), called an<br />

algebra, which possesses a few important properties. Also, K is not required to be the closed<br />

interval [a,b], but rather is allowed to be any compact topological space. This result is known<br />

as the Stone-Weierstrass theorem, and its proof is accomplished in two main steps. First,<br />

we prove a special case of the theorem for the space C(K, R) which relies on the classical<br />

Weierstrass approximation theorem. We then use this result to prove the theorem in its full<br />

strength. Before we begin, a few preliminary results are in order.<br />

Definition. Let K be compact, A be a scalar field, and let A be a linear subspace over<br />

A of C(K,A) such that for f,g ∈ A, f · g ∈ A, where (f · g)(x) = f(x) · g(x). Then A is<br />

called an algebra of continuous functions. A is said to be real or complex if A is R or C.<br />

An algebra of continuous functions is merely a ring of continuous functions, inheriting<br />

addition and multiplication from A, and which is closed under scalar multiplication.<br />

Definition. Let A be a subset of the metric space (C(K,A),ρ∞), where A is R or C.<br />

Then the closure of A in C(K,A) is called the uniform closure of A, and A is said to be<br />

uniformly closed in C(K,A).<br />

The uniform closure of an algebra A can be thought of as the set of all functions in<br />

C(K,A) which are the limit of a fundamental sequence in A.<br />

Theorem. Let A be an algebra of bounded functions. Then the uniform closure B of A<br />

is a uniformly closed algebra.<br />

Proof. For f ∈ B, g ∈ B, let {fn}, {gn} be uniformly convergent sequences in A such<br />

that fn → f, gn → g. Since the fi and gi are bounded, fn + gn → f + g, fngn → fg,

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