Math 220 March 7 I. If 1200 cm2 of material is available to make a ...

9.
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Answer:
Answer:
2x − sin(x)
lim
x→0 2x − tan(x)
2x − sin(x)
lim
x→0 2x − tan(x)
= lim
x→0
= 1
1
= 1
0
0
2 − cos(x)
2 − sec2 (x)
lim
x→0 +
1 1
−
x ex
− 1
lim
x→0 +
1 1
−
x ex
− 1
= lim
x→0 +
x e − 1 − x
x(ex
0
− 1) 0
L.H.
= lim
x→0 +
ex − 1
ex − 1 + xex
0
0
L.H.
= lim
x→0 +
= 1
2
e x
e x + e x + xe x
lim (sin(x) ln(x))
x→0 +
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