Math 220 March 7 I. If 1200 cm2 of material is available to make a ...

15.
Answer:
ln(y) = ln( lim
x→1 + (x)2/(1−x) )
= lim
x→1 +
2
1 − x ln(x)
= lim
x→1 +
2 ln(x) 0
1 − x 0
L.H.
= lim
x→1 +
2/x
−1
= −2
y = e ln(y)
= e −2
x 2
lim e + x
x→∞
1/(1−x) 14