P7 – Scattering of Surface Plasmon Polaritons by Gold ... - repetit.dk
P7 – Scattering of Surface Plasmon Polaritons by Gold ... - repetit.dk
P7 – Scattering of Surface Plasmon Polaritons by Gold ... - repetit.dk
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kSPP<br />
S in =<br />
<br />
2 −2akSPPz 2<br />
a − 1 e cos (kSPPx + ωt) ˆx<br />
2.4. VECTORIAL MODEL<br />
µ0ω<br />
<br />
akSPP 2<br />
+ 1 − a<br />
µ0ω<br />
e −2akSPPz <br />
sin (kSPPx + ωt) cos (kSPPx + ωt) ˆy<br />
= kSPP 2 −2akSPPz<br />
a − 1 e ˆx<br />
2µ0ω<br />
since the time average <strong>of</strong> the y component is zero. Below the surface the poynting vector is<br />
<br />
4<br />
< −a kSPP<br />
S in =<br />
µ0ω<br />
4 a kSPP<br />
+<br />
µ0ωa<br />
= −a4 kSPP<br />
2µ0ω<br />
<br />
1<br />
− 1<br />
a2 <br />
1<br />
− 1<br />
a2 <br />
1<br />
− 1<br />
a2 e 2kSPPz/a cos 2 <br />
(kSPPx + ωt) ˆx<br />
e 2kSPPz/a <br />
sin (kSPPx + ωt) cos (kSPPx + ωt) ˆy<br />
e 2kSPPz/a ˆx<br />
(2.94)<br />
(2.95)<br />
By integrating these expressions according to Eqn. 2.86 the following expression for the incident<br />
power is obtained<br />
Pin = 1<br />
2k0<br />
ε0<br />
µ0<br />
1 − a2 4<br />
1 − a<br />
2a<br />
<br />
(2.96)<br />
By doing the same calculation but with the field above the surface only, the same result without<br />
the −a 4 term is obtained. This shows that the −a 4 term stems from the flux <strong>of</strong> energy below<br />
the surface, and that the energy flux can be concentrated above the surface <strong>by</strong> making −εm<br />
significantly larger than εr. The numerator <strong>of</strong> Eqn. 2.86 can be calculated <strong>by</strong> a procedure<br />
similar to the one just shown. The scattered field is first determined, then the magnetic field,<br />
and the poynting vector can then be calculated and averaged in time. The calculation is not<br />
made here. The result is [Evlyukhin and Bozhevolnyi, 2005]<br />
〈SSPP〉 = 1<br />
k0<br />
ε0<br />
µ0<br />
|A| 2<br />
2 α0<br />
e<br />
1 + 2ξβ<br />
−2akSPP(z+2zp) (1 + ηp cos φ) 2 1 − a2 πρ<br />
By carrying out the integration and using Eqn. 2.86 the scattering cross section becomes<br />
(2.97)<br />
σSPP (φ) dφ = 2 |A| 2<br />
2 α0 (1 + ηp cos φ)<br />
1 + 2ξβ<br />
2<br />
e<br />
πkSPP<br />
−4akSPPzp (2.98)<br />
From this expression it is seen that the cross section decays exponentially as the scatterersurface<br />
distance zp increases. This makes good sense because the SPP field decreases exponentially<br />
away from the surface into the dieletric, so that the scattering will also decrease exponentially.<br />
The angular dependence <strong>of</strong> the scattering cross section is determined <strong>by</strong> (1 + ηp cos φ)<br />
37