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<strong>Problem</strong> 10<br />
First, figure out the electricity usage (with increased efficiency) given this consumption<br />
limitation:<br />
(x hours) x (0.6 kWh / hour) = 2,880 kWh’s<br />
x = (2,880 kWh’s) x (1 hour / 0.6 kWh’s)<br />
x = 4,800 hours<br />
Next, use usage as Q in the given equation to find the new P ($/hour):<br />
Q = = 6,000 – 20,000P<br />
4800 = = 6,000 – 20,000P<br />
-1,200 = -20,000P<br />
P = $0.06/hour<br />
Finally, figure out the tax (T) needed to reach the consumption goal:<br />
$0.075+
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