02.08.2013 Views

Representations of positive projections 1 Introduction - Mathematics ...

Representations of positive projections 1 Introduction - Mathematics ...

Representations of positive projections 1 Introduction - Mathematics ...

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Corollary 3.5 Let (X ) be a representation space for the Dedekind complete<br />

Riesz space L with weak order unit 0 w 2 L. Then (X ) is a representation<br />

space for (L u w) as well and we may actually take cL u = M (X ).<br />

Pro<strong>of</strong>. Let b L be an ideal such that Mb (X ) L M (X ) and<br />

: bL ! L a surjective -order continuous Riesz homomorphism. Let b =<br />

jMb(X ), then b : Mb (X ) ! Lw is a surjective -order continuous Riesz<br />

homomorphism as well. Since L is Dedekind complete, (L u ) w = Lw and so<br />

it follows immediately from Lemma 3.2 that (X ) is a representation space<br />

for (L u w). Taking cL u as de ned by (5) we have cL u = M(X ). Indeed,<br />

let 0 g 2 M(X ) be given and let fgkg 1<br />

be a disjoint sequence in<br />

k=1<br />

Mb(X ) such that supk gk = g. Then f b(gk)g 1<br />

is a disjoint system in L<br />

k=1<br />

and so supk b(gk) = f 2 Lu exists. Since b is a -order continuous Riesz<br />

homomorphism it follows that<br />

b(g ^ n1X) = b sup (gk ^ n1X) =sup<br />

k<br />

k<br />

b (gk ^ n1X) f<br />

for all n 2 N and so g 2 cL u . Note that, by -order continuity, the corresponding<br />

Riesz homomorphism u : M(X ) ! L u coincides with on bL.<br />

Next we make some remarks concerning the relation between -ideal in<br />

ideals in M(X ) and Boolean -ideals in . We introduce some further<br />

notation. Given a -ideal N we write<br />

M(N) =ff 2 M(X ) : fx 2 X : f(x) 6= 0g2Ng<br />

and Mb(N) = M(N) \ Mb(X ). Then M(N) and Mb(N) are -ideals in<br />

M(X ) and Mb(X ) respectively. Now assume that E is an ideal in<br />

M(X ) such thatMb(X ) E. It is clear that E \M(N) isa -ideal in E<br />

whenever N is a -ideal in . We claim that all -ideals in E are <strong>of</strong> this form.<br />

Indeed, given a -ideal N in E we de ne N = fF 2 :1F 2 Ng and we will<br />

show that N = E \ M(N). Take f 2 N and let F = fx 2 X : f(x) 6= 0g.<br />

Then n jfj ^1X 2 N for all n 2 N and n jfj ^ 1X " 1F , so 1F 2 N,<br />

i.e., F 2 N and hence f 2 E \ M(N). Conversely, if f 2 E and F =<br />

fx 2 X : f(x) 6= 0g2N, then jfj^n1F 2 N for all n 2 N and jfj^n1F "jfj,<br />

so jfj 2N and hence f 2 N.<br />

Assume that L is a Dedekind -complete Riesz space with weak order<br />

unit 0 w 2 L and that (X ) is a representation space for (L w)<br />

with representation : bL ! L, where Mb(X ) bL M(X ) is<br />

an ideal. Then Ker ( ) is a -ideal in bL and it follows from the above<br />

18

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!