Betti numbers of modules over Noetherian rings with ... - IPM
Betti numbers of modules over Noetherian rings with ... - IPM
Betti numbers of modules over Noetherian rings with ... - IPM
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Chapter 1: Preliminaries 6<br />
i < 0, then QM(t) is an ordinary polynomial <strong>with</strong> integer coefficients in the variable<br />
t. If more<strong>over</strong> d = 0, then HM(t) = QM(t), i.e., the Hilbert series is a polynomial.<br />
If M has a finite graded free resolution<br />
· · · −→ <br />
R(−j) βs<br />
<br />
j −→ · · · −→ R(−j) β1<br />
<br />
j −→<br />
then<br />
j∈Z<br />
j∈Z<br />
j∈Z<br />
R(−j) β0 j −→ M −→ 0,<br />
HM(t) = HR(t) <br />
(−1) i β R i j(M)t j . (1.2)<br />
i,j<br />
More<strong>over</strong>, if x1, · · · , xr is a regular sequence <strong>over</strong> M <strong>of</strong> homogeneous elements <strong>of</strong><br />
degree 1, then the Hilbert function <strong>of</strong> the n − r-dimensional quotient module ¯ M =<br />
M/(x1, · · · , xr)M is<br />
and in particular, Q ¯ M(t) = QM(t).<br />
HM(t) ¯ = QM(t)<br />
, (1.3)<br />
(1 − t) n−r<br />
These properties suggest effective methods for computing the Hilbert series <strong>of</strong> a<br />
finitely generated graded module <strong>over</strong> the polynomial ring R = K[X1, · · · , Xn], where<br />
K is a field.<br />
The Hilbert series <strong>of</strong> R, which has dimension n, can be obtained by considering<br />
the maximal regular sequence X1, · · · , Xn <strong>of</strong> R, and the Hilbert function <strong>of</strong> the<br />
0-dimensional quotient ring ¯ R = R/(X1, · · · , Xr), which is the same as K. Now<br />
H(K, 0) = 1, and H(K, i) = 0 for all i = 0. Hence HK(t) = 1. It follows that QR(t) is<br />
the constant polynomial 1, so that<br />
HR(t) =<br />
1<br />
.<br />
(1 − t) n