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Applied Calculus Math 215 - University of Hawaii

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12 CHAPTER 1. SOME BACKGROUND MATERIAL<br />

Example 1.6. The lines<br />

2x +5y=7 & 4x+10y=15<br />

are parallel and have no intersection point.<br />

To see this, observe that the first equation, multiplied with 2, is 4x +<br />

10y = 14. There are no numbers x and y for which 4x +10y =14and<br />

4x+10y= 15 at the same time. Thus this system <strong>of</strong> two equations in two<br />

unknowns has no solution, and the two lines do not intersect. ♦<br />

To be parallel also means to have the same slope. If the lines are not<br />

vertical (b = 0andB= 0), then the condition says that the slopes −a/b <strong>of</strong><br />

the line l1 and −A/B <strong>of</strong> the line l2 are the same. If both lines are vertical,<br />

then we have not assigned a slope to them.<br />

If Ab = aB, then the lines are not parallel to each other, and one can<br />

show that they intersect in exactly one point. You saw an example above.<br />

If Aa = −bB, then the lines intersect perpendicularly. Assuming that<br />

neither line is vertical (b = 0andB= 0), the equation may be written as<br />

a A<br />

×<br />

b B<br />

= −1.<br />

This means that the product <strong>of</strong> the slopes <strong>of</strong> the lines (−a/b is the slope<br />

<strong>of</strong>thefirstlineand−A/B the one <strong>of</strong> the second line) is −1. The slope<br />

<strong>of</strong> one line is the negative reciprocal <strong>of</strong> the slope <strong>of</strong> the other line. This is<br />

the condition which you have probably seen before for two lines intersecting<br />

perpendicularly.<br />

Example 1.7. The lines<br />

3x − y =1 & x+3y=7<br />

have slopes 3 and −1/3, resp., and intersect perpendicularly in (x, y) =<br />

(1, 2). ♦<br />

Exercise 6. Find the intersection points <strong>of</strong> the lines<br />

l1(x) =3x+4 & l2(x)=4x−5.<br />

Sketch the lines and verify your calculation <strong>of</strong> the intersection point.

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