havoc automated exam system

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ime in priimek: vpisna ˇst.:
Fakulteta za elektrotehniko, Univerza v Ljubljani primeri ˇstevk:
1. test iz predmeta HAvOc (UNI) 2.3.2011
1. Wheatstone bridge without null indicator has the following values of resistors: R1 = 5 Ω,
R2 = 4 Ω, R3 = 7 Ω in R4 = 4 Ω. We have connected the bridge to a DC voltage source
U = 1V.
AÇVB
I
+
-
R R
1
Ug A B
R R
a) Determine the electric potential of junction B.
.
.
= 364 mV BÇVB = 5 V CÇVB = 3.64 V DÇVB = 0 V
b) What is the value of voltage UAB?
AÇUAB
.
= 80.8 mV BÇUAB
c) Determine the current through resistor R1.
.
= 808 mV CÇUAB
.
= −80.8 mV DÇUAB = 333 mV
AÇI . = 111 mA BÇI . = 208 mA CÇI= 20 A DÇI= 50 mA
2. The circuit is made of three resistors: R1 = 5 Ω, R2 = 2 Ω in R3 = 2 Ω. Voltage
source is U = 10V.
R R R
1 2 3
a) What is the sum voltage on resistors R1 and R2?
.
= 2.86 V BÇUR1+R2 = 35 V CÇUR1+R2 = 5 V DÇUR1+R2 = 10 V
AÇUR1+R2
b) How much is the voltage on resistor R3?
.
= 2.86 V BÇUR3 = 0 V CÇUR3 = 10 V DÇUR3 = 5 V
AÇUR3
c) Determine the current through R2!
AÇI . = 1.43 A BÇI= 20 A CÇI . = 1.11 A DÇI= 7.8 A
3.
AÇ
Which circuits represents debounced
BÇ
switch?
4. The entropy of isolated thermodynamical system CÇ DÇ
AÇcan only decrease. BÇis always zero. CÇcan only increase. DÇis always positive constant.
This row can be used for further instructions.
Berkopec
Copyright2011 hAvOc= Penič ver. 2.2 ⋆ ←→ ⋆ podpis: 0/0/4
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+ -
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0 0 0 4 0 4 5 0 0 0 0 1 8
ime in priimek: vpisna ˇst.:
Fakulteta za elektrotehniko, Univerza v Ljubljani primeri ˇstevk:
1. test iz predmeta HAvOc (UNI) 2.3.2011
1. The entropy of isolated thermodynamical system
AÇis always positive constant. BÇis always zero. CÇcan only decrease. DÇcan only increase.
2. The circuit is made of three resistors: R1 = 10 Ω, R2 = 2 Ω in R3 = 9 Ω. Voltage
source is U = 10V.
R R R
1 2 3
a) What is the sum voltage on resistors R1 and R2?
.
AÇUR1+R2 = 10 V BÇUR1+R2 = 13.3 V CÇUR1+R2 = 120 V DÇUR1+R2 = 20 V
b) How much is the voltage on resistor R3?
.
.
= 13.3 V BÇUR3 = 0 V CÇUR3 = 5 V DÇUR3 = 1.11 V
AÇUR3
c) Determine the current through R2!
AÇI . = 476 mA BÇI= 7.8 A CÇI= 1.3 A DÇI . = 833 mA
3.
AÇ
Which circuits represents debounced
BÇ
switch?
CÇ DÇ
4. Wheatstone bridge without null indicator has the following values of resistors: R1 = 5 Ω,
R2 = 5 Ω, R3 = 2 Ω in R4 = 3 Ω. We have connected the bridge to a DC voltage source
U = 1V.
I R1 R3
a) Determine the electric potential of junction B.
U
+ -
+
-
Ug A B
R R
AÇVB = 600 mV BÇVB = 6 V CÇVB = 500 mV DÇVB = 5 V
b) What is the value of voltage UAB?
AÇUAB = 333 mV BÇUAB = 500 mV CÇUAB = 250 mV DÇUAB = −100 mV
c) Determine the current through resistor R1.
AÇI= 15 A BÇI . = 268 mA CÇI= 300 mA DÇI= 100 mA
This row can be used for further instructions.
Berkopec
Copyright2011 hAvOc= Penič ver. 2.2 ⋆ ←→ ⋆ podpis: 0/1/4
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2
4

0 0 0 4 0 4 5 0 0 0 0 2 5
ime in priimek: vpisna ˇst.:
Fakulteta za elektrotehniko, Univerza v Ljubljani primeri ˇstevk:
1. test iz predmeta HAvOc (UNI) 2.3.2011
1. The entropy of isolated thermodynamical system
AÇis always zero. BÇis always positive constant. CÇcan only decrease. DÇcan only increase.
2. Wheatstone bridge without null indicator has the following values of resistors: R1 = 15 Ω,
R2 = 5 Ω, R3 = 9 Ω in R4 = 4 Ω. We have connected the bridge to a DC voltage source
U = 1V.
I
+
-
R R
1
Ug A B
R R
a) Determine the electric potential of junction B.
.
.
AÇVB = 5 V BÇVB = 308 mV CÇVB = 1 V DÇVB = 3.08 V
b) What is the value of voltage UAB?
AÇUAB
.
= −57.7 mV BÇUAB
c) Determine the current through resistor R1.
.
= 144 mV CÇUAB = 333 mV DÇUAB
2
.
= −442 mV
AÇI . = 153 mA BÇI . = 127 mA CÇI= 50 mA DÇI= 33 A
3. The circuit is made of three resistors: R1 = 10 Ω, R2 = 4 Ω in R3 = 3 Ω. Voltage
source is U = 10V.
AÇUR1+R2
R R R
1 2 3
a) What is the sum voltage on resistors R1 and R2?
.
.
= 46.7 V BÇUR1+R2 = 20 V CÇUR1+R2 = 10 V DÇUR1+R2 = 2.14 V
b) How much is the voltage on resistor R3?
AÇUR3
.
= 3.33 V BÇUR3 = 0 V CÇUR3
c) Determine the current through R2!
.
= 2.14 V DÇUR3
U
+ -
.
= 46.7 V
AÇI= 30 A BÇI . = 714 mA CÇI= 1.3 A DÇI= 7.8 A
4.
AÇ
Which circuits represents debounced
BÇ
switch?
CÇ DÇ
This row can be used for further instructions.
Berkopec
Copyright2011 hAvOc= Penič ver. 2.2 ⋆ ←→ ⋆ podpis: 0/2/4
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3
4

0 0 0 4 0 4 5 0 0 0 0 3 2
ime in priimek: vpisna ˇst.:
Fakulteta za elektrotehniko, Univerza v Ljubljani primeri ˇstevk:
1. test iz predmeta HAvOc (UNI) 2.3.2011
1. The circuit is made of three resistors: R1 = 5 Ω, R2 = 3 Ω in R3 = 9 Ω. Voltage
source is U = 10V.
AÇUR1+R2
R R R
1 2 3
a) What is the sum voltage on resistors R1 and R2?
.
.
= 8.89 V BÇUR1+R2 = 80 V CÇUR1+R2 = 11.3 V DÇUR1+R2 = 10 V
b) How much is the voltage on resistor R3?
.
= 11.3 V BÇUR3 = 5 V CÇUR3 = 10 V DÇUR3 = 0 V
AÇUR3
c) Determine the current through R2!
AÇI= 0 A BÇI= 7.8 A CÇI= 1.25 A DÇI= 90 A
2. Wheatstone bridge without null indicator has the following values of resistors: R1 = 15 Ω,
R2 = 5 Ω, R3 = 6 Ω in R4 = 6 Ω. We have connected the bridge to a DC voltage source
U = 1V.
a) Determine the electric potential of junction B.
I
U
+ -
+
-
R R
1
Ug A B
R R
AÇVB = 500 mV BÇVB = 1.2 V CÇVB = 1 V DÇVB = 0 V
b) What is the value of voltage UAB?
AÇUAB = −250 mV BÇUAB = 333 mV CÇUAB = 750 mV DÇUAB = 500 mV
c) Determine the current through resistor R1.
AÇI= 50 mA BÇI . = 31.3 mA CÇI . = 133 mA DÇI= 32 A
3. The entropy of isolated thermodynamical system
AÇis always zero. BÇis always positive constant. CÇcan only decrease. DÇcan only increase.
AÇ BÇ CÇ DÇ
4. Which circuits represents debounced switch?
This row can be used for further instructions.
Berkopec
Copyright2011 hAvOc= Penič ver. 2.2 ⋆ ←→ ⋆ podpis: 0/3/4
Foˇsnarič
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3
4

0 0 0 4 0 4 5 0 0 0 0 4 9
ime in priimek: vpisna ˇst.:
Fakulteta za elektrotehniko, Univerza v Ljubljani primeri ˇstevk:
1. test iz predmeta HAvOc (UNI) 2.3.2011
1. Wheatstone bridge without null indicator has the following values of resistors: R1 = 10 Ω,
R2 = 5 Ω, R3 = 6 Ω in R4 = 4 Ω. We have connected the bridge to a DC voltage source
U = 1V.
I
+
-
R R
1
Ug A B
R R
a) Determine the electric potential of junction B.
.
AÇVB = 4 V BÇVB = 667 mV CÇVB = 400 mV DÇVB = 0 V
b) What is the value of voltage UAB?
AÇUAB
.
= 66.7 mV BÇUAB = 500 mV CÇUAB
c) Determine the current through resistor R1.
.
= −66.7 mV DÇUAB
2
.
= −267 mV
AÇI . = 66.7 mA BÇI= 40 mA CÇI= 25 A DÇI . = 174 mA
2. The circuit is made of three resistors: R1 = 10 Ω, R2 = 5 Ω in R3 = 7 Ω. Voltage
source is U = 10V.
a) What is the sum voltage on resistors R1 and R2?
AÇUR1+R2 = 20 V BÇUR1+R2 = 150 V CÇUR1+R2 = 10 V DÇUR1+R2
b) How much is the voltage on resistor R3?
AÇUR3 = 5 V BÇUR3 = 0 V CÇUR3
c) Determine the current through R2!
R R R
1 2 3
U
+ -
.
= 4.67 V
.
= 1.43 V DÇUR3 = 10 V
AÇI= 0 A BÇI= 70 A CÇI . = 455 mA DÇI . = 667 mA
3. The entropy of isolated thermodynamical system
AÇcan only increase. BÇcan only decrease. CÇis always zero. DÇis always positive constant.
AÇ BÇ CÇ DÇ
4. Which circuits represents debounced switch?
This row can be used for further instructions.
Berkopec
Copyright2011 hAvOc= Penič ver. 2.2 ⋆ ←→ ⋆ podpis: 0/4/4
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