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3 = 10<br />

3<br />

The cycloidal part of the curve will start at<br />

= 2 ( 3 +4 )/ 2<br />

Therefore, the dwell period will be<br />

1<br />

+<br />

<br />

4 2 < < 2 3 ( +4 )/ 2<br />

And the dwell distance will b,<br />

y = 40<br />

The cycloidal part of the curve occurs when<br />

2 ( 3 +4 )/ 2 < < 2 3 / 2<br />

And<br />

<br />

y3 = L3 L3 3<br />

3<br />

1 23<br />

sin<br />

2 <br />

The curve will be shifted because L3 is 50. Therefore,<br />

3<br />

3<br />

y = y3 10 = L3 L3 3 1 23<br />

sin<br />

2 10<br />

The second harmonic part of the curve occurs when<br />

And<br />

2 3 / 2 < < 2<br />

y4 = L4<br />

2<br />

<br />

1+ cos<br />

<br />

4<br />

The displacement diagram is shown in the following:<br />

3<br />

- 359 -

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