1. Advanced Data Structure using C++

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LECTURE NOTES OF ADVANCED DATA STRUCTURE (MT-CSE 110) approach, however, has an inherent disadvantage. When each of the piles is being sorted, the other piles have to be kept aside and kept track of. If, instead, we follow the 'counterintuitive' aproach of first sorting the cards by value, this problem is eliminated. After the first step, the four seperate piles are combined in order and then sorted by suit. If a stable sorting algorithm (i.e. one which resolves a tie by keeping the number obtained first in the input as the first in the output) it can be easily seen that correct final results are obtained. As has been mentioned, the sorting of numbers proceeds by sorting the least significant to most significant digit. For sorting each of these digit groups, a stable sorting algorithm is needed. Also, the elements in this group to be sorted are in the fixed range of 0 to 9. Example: To illustrate the bucket sort method, consider following list of numbers: 121, 70, 965, 432, 12, 577, 683 Solution: Pass 1: 121 70 965 432 12 577 12 683 70 121 432 683 965 577 Input 0 1 2 3 4 5 6 7 8 9 Pass 2: Prepared By : Er. Harvinder Singh Assist Prof., CSE, H.C.T.M (Kaithal) Page ‐ 8 ‐
70 121 432 12 638 LECTURE NOTES OF ADVANCED DATA STRUCTURE (MT-CSE 110) 965 70 577 12 121 432 965 577 683 Input 0 1 2 3 4 5 6 7 8 9 Pass 3: 70 121 432 12 638 965 70 577 12 121 432 577 683 965 Input 0 1 2 3 4 5 6 7 8 9 After pass 3, when the numbers are collected, they are in the following order Prepared By : Er. Harvinder Singh Assist Prof., CSE, H.C.T.M (Kaithal) Page ‐ 9 ‐
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