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Day 7 - UH Department of Mathematics

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Math 1314<br />

Lesson 11: Exponential Functions as Mathematical Models<br />

x<br />

x<br />

Exponential models can be written in two forms: f ( x) = a ⋅ e or g ( x) a b<br />

= ⋅ . In the first<br />

model, the base <strong>of</strong> the exponent is the number e, which is approximately 2.71828…. In the<br />

second model, the base <strong>of</strong> the exponent is a positive number other than 1. In both cases, the<br />

variable is located in the exponent, and that’s why these are called exponential models.<br />

Exponential functions can be either increasing or decreasing.<br />

bx<br />

The function f ( x) = a ⋅ e is an exponential growth function and it’s increasing.<br />

bx<br />

The function f ( x) = a ⋅ e − is an exponential decay function and it’s decreasing.<br />

In both equations the variable a is called the initial amount and b is called the growth or decay<br />

constant, depending on the type <strong>of</strong> function.<br />

x<br />

For a function <strong>of</strong> the form g ( x) a b<br />

and is an exponential decay function if 0 < b < 1.<br />

= ⋅ , the function is an exponential growth function if b > 1<br />

We can also compute the rate at which an exponential function is increasing or decreasing.<br />

We’ll do this by finding a numerical derivative.<br />

We can use the regression feature to find an exponential equation for data that’s given.<br />

Example 1: Identify each function as a growth function or a decay function. Find the initial<br />

value. Calculate f (30) and f '(30) .<br />

a.<br />

0.285t<br />

= e −<br />

b. g( x ) = 38.6(1.0489) x<br />

f ( t) 12.8<br />

Example 2: Suppose the points (0, 10000) and (2, 10940) lie on the graph <strong>of</strong> a function. Find<br />

bx<br />

f x = a ⋅ e using GeoGebra, assuming that the<br />

the equation <strong>of</strong> the function in the form ( )<br />

function is exponential.<br />

Begin by entering the two given points in the spreadsheet, then make a list.<br />

Command:<br />

Answer:<br />

Lesson 11 – Exponential Functions as Mathematical Models 1


Uninhibited Exponential Growth<br />

Some common exponential applications model uninhibited exponential growth. This means<br />

that there is no “upper limit” on the value <strong>of</strong> the function. It can simply keep growing and<br />

growing. Problems <strong>of</strong> this type include population growth problems and growth <strong>of</strong> investment<br />

assets.<br />

Example 3: A biologist wants to study the growth <strong>of</strong> a certain strain <strong>of</strong> bacteria. She starts<br />

with a culture containing 25,000 bacteria. After three hours, the number <strong>of</strong> bacteria has grown to<br />

63,000. Assume the population grows exponentially and the growth is uninhibited.<br />

bx<br />

a. Find the equation <strong>of</strong> the function in the form f ( x) = a ⋅ e using GGB.<br />

State the two points given in the problem.<br />

Enter the two points in the spreadsheet, then make a list.<br />

Command:<br />

Answer:<br />

b. How many bacteria will be present in the culture 6 hours after she started her study?<br />

Example 4: The sales from company ABC for the years 1998 – 2003 are given below.<br />

Year 1998 1999 2000 2001 2002 2003<br />

pr<strong>of</strong>its in millions <strong>of</strong> dollars 51.4 53.2 55.8 56.1 58.1 59.0<br />

Rescale the data so that x = 0 corresponds to 1998. Begin by making a list.<br />

a. Find an exponential regression model for the data.<br />

Command:<br />

Answer:<br />

b. Find the rate at which the company's sales were changing in 2007.<br />

Command:<br />

Answer:<br />

Lesson 11 – Exponential Functions as Mathematical Models 2


Exponential Decay<br />

Example 5: At the beginning <strong>of</strong> a study, there are 50 grams <strong>of</strong> a substance present. After 17<br />

days, there are 38.7 grams remaining. Assume the substance decays exponentially.<br />

a. State the two points given in the problem.<br />

Enter the two points in the spreadsheet and make a list.<br />

b. Find an exponential regression model.<br />

Command:<br />

Answer:<br />

c. What will be the rate <strong>of</strong> decay on day 40 <strong>of</strong> the study?<br />

Command:<br />

Answer:<br />

Exponential decay problems frequently involve the half-life <strong>of</strong> a substance. The half-life <strong>of</strong> a<br />

substance is the time it takes to reduce the amount <strong>of</strong> the substance by one-half.<br />

Example 6: A certain drug has a half-life <strong>of</strong> 4 hours. Suppose you take a dose <strong>of</strong> 1000<br />

milligrams <strong>of</strong> the drug.<br />

a. State the two points given in the problem.<br />

Enter the two points in the spreadsheet and make a list.<br />

b. Find an exponential regression model.<br />

Command:<br />

Answer:<br />

c. How much <strong>of</strong> it is left in your bloodstream 28 hours later?<br />

Command:<br />

Answer:<br />

Lesson 11 – Exponential Functions as Mathematical Models 3


Example 7: The half-life <strong>of</strong> Carbon 14 is 5770 years.<br />

a. State the two points given in the problem.<br />

Enter the two points in the spreadsheet and make a list.<br />

b. Find an exponential regression model.<br />

Command:<br />

Answer:<br />

c. Bones found from an archeological dig were found to have 22% <strong>of</strong> the amount <strong>of</strong> Carbon 14<br />

that living bones have. Find the approximate age <strong>of</strong> the bones.<br />

Command:<br />

Answer:<br />

Limited Growth Models<br />

Some exponential growth is limited; here’s an example:<br />

A worker on an assembly line performs the same task repeatedly throughout the workday. With<br />

experience, the worker will perform at or near an optimal level. However, when first learning to<br />

do the task, the worker’s productivity will be much lower. During these early experiences, the<br />

worker’s productivity will increase dramatically. Then, once the worker is thoroughly familiar<br />

with the task, there will be little change to his/her productivity.<br />

The function that models this situation will have the form Q( t)<br />

= C − Ae −kt .<br />

This model is called a learning curve and the graph <strong>of</strong> the function will look something like<br />

this:<br />

The graph will have a y intercept at C – A and a horizontal asymptote at y = C. Because <strong>of</strong> the<br />

horizontal asymptote, we know that this function does not model uninhibited growth.<br />

Lesson 11 – Exponential Functions as Mathematical Models 4


Example 8: Suppose your company’s HR department determines that an employee will be able<br />

0.5t<br />

to assemble Q( t) = 50 − 30e − products per day, t months after the employee starts working on<br />

the assembly line. Enter the function in GGB.<br />

a. How many units can a new employee assemble as s/he starts the first day at work?<br />

b. How many units should an employee be able to assemble after two months at work?<br />

c. How many units should an experienced worker be able to assemble?<br />

d. At what rate is an employee’s productivity changing 4 months after starting to work?<br />

Logistic Functions<br />

The last growth model that we will consider involves the logistic function. The general form <strong>of</strong><br />

A<br />

the equation is Q( t)<br />

= and the graph looks something like this:<br />

kt<br />

1 + Be −<br />

If we looked at this graph up to around x = 2 and didn’t consider the rest <strong>of</strong> it, we might think<br />

that the data modeled was exponential. Logistic functions typically reach a saturation point – a<br />

point at which the growth slows down and then eventually levels <strong>of</strong>f. The part <strong>of</strong> this graph to<br />

the right <strong>of</strong> x = 2 looks more like our learning curve graph from the last example. Logistic<br />

functions have some <strong>of</strong> the features <strong>of</strong> both types <strong>of</strong> models.<br />

Note that the graph has a limiting value at y = 5. In the context <strong>of</strong> a logistic function, this<br />

asymptote is called the carrying capacity. In general the carrying capacity is A from the<br />

formula above.<br />

Lesson 11 – Exponential Functions as Mathematical Models 5


Logistic curves are used to model various types <strong>of</strong> phenomena and other physical situations such<br />

as population management. Suppose a number <strong>of</strong> animals are introduced into a protected game<br />

reserve, with the expectation that the population will grow. Various factors will work together to<br />

keep the population from growing exponentially (in an uninhibited manner). The natural<br />

resources (food, water, protection) may not exist to support a population that gets larger without<br />

bound. Often such populations grow according to a logistic model.<br />

Example 9: A population study was commissioned to determine the growth rate <strong>of</strong> the fish<br />

population in a certain area <strong>of</strong> the Pacific Northwest. The function given below models the<br />

population where t is measured in years and N is measured in millions <strong>of</strong> tons. Enter the<br />

function in GGB.<br />

2.4<br />

N( t)<br />

=<br />

0.338t<br />

1 + 2.39e −<br />

a. What was the initial number <strong>of</strong> fish in the population?<br />

b. What is the carrying capacity in this population?<br />

c. What is the fish population after 3 years?<br />

d. How fast is the fish population changing after 2 years?<br />

Lesson 11 – Exponential Functions as Mathematical Models 6


Math 1314<br />

Lesson 12<br />

Curve Analysis (Polynomials)<br />

This lesson will cover analyzing polynomial functions using GeoGebra.<br />

Suppose your company embarked on a new marketing campaign and was able to track sales<br />

based on it. The graph below gives the number <strong>of</strong> sales in thousands shown t days after the<br />

campaign began.<br />

Now suppose you are assigned to analyze this information. We can use calculus to answer the<br />

following questions:<br />

When are sales increasing or decreasing? (Note that the graph stops at t = 40.)<br />

What is the maximum number <strong>of</strong> sales in the given time period?<br />

Where does the growth rate change?<br />

Etc.<br />

Calculus can’t answer the “why” questions, but it can give you some information you need to<br />

start that inquiry.<br />

There will be several features <strong>of</strong> a polynomial function that we’ll need to find. Let’s start with a<br />

few College Algebra topics.<br />

An example <strong>of</strong> a polynomial function is<br />

f ( x) ( x 2)( x 1) ( x 1)<br />

3 2<br />

= − − + . Its graph looks like:<br />

*The domain <strong>of</strong> any polynomial function is ( ) , −∞ ∞ . Polynomial functions have no asymptotes.<br />

*To find the roots/zeros/x-intercepts/solutions <strong>of</strong> any function, set the function equal to zero and<br />

solve for x. Or you may simply use the root or roots command in GGB.<br />

*To find the y-intercept for any function, set x = 0 and calculate.<br />

*The range <strong>of</strong> any polynomial is easier found by looking at the graph <strong>of</strong> the function.<br />

Lesson 12 – Curve Analysis (Polynomials) 1


3 2<br />

Example 1: Let f ( x) = x − 3x − 13x<br />

+ 15 . Enter the function in GGB.<br />

a. Find any x-intercepts <strong>of</strong> the function.<br />

Command:<br />

Answer:<br />

b. Find any y-intercept <strong>of</strong> the function.<br />

Command:<br />

Answer:<br />

Intervals on Which a Function is Increasing/Decreasing<br />

Definition: A function is increasing on an interval (a, b) if, for any two numbers x1<br />

and x2<br />

in<br />

(a, b), f ( x1 ) < f ( x2<br />

) , whenever x<br />

1<br />

< x2<br />

. A function is decreasing on an interval (a, b) if, for<br />

any two numbers x1<br />

and x<br />

2<br />

in (a, b), f ( x1 ) > f ( x2<br />

) , whenever x<br />

1<br />

< x2<br />

.<br />

In other words, if the y values are getting bigger as we move from left to right across the graph <strong>of</strong><br />

the function, the function is increasing. If they are getting smaller, then the function is<br />

decreasing. We will state intervals <strong>of</strong> increase/decrease using interval notation. The interval<br />

notation will consists <strong>of</strong> corresponding x-values wherever y-values are getting bigger/smaller.<br />

Example 2: Given the following graph <strong>of</strong> a function, state the intervals on which the function is:<br />

a. increasing. b. decreasing.<br />

We can use calculus to determine intervals <strong>of</strong> increase and intervals <strong>of</strong> decrease. A function can<br />

change from increasing to decreasing or from decreasing to increasing at its critical numbers, so<br />

we start with a definition <strong>of</strong> critical numbers:<br />

The critical numbers <strong>of</strong> a polynomial function are all values <strong>of</strong> x that are in the domain <strong>of</strong> f<br />

where f ′( x) = 0 (the tangent line to the curve is horizontal).<br />

A function is increasing on an interval if the first derivative <strong>of</strong> the function is positive for every<br />

number in the interval. A function is decreasing on an interval if the first derivative <strong>of</strong> the<br />

function is negative for every number in the interval.<br />

Lesson 12 – Curve Analysis (Polynomials) 2


Example 3: The graph given below is the first derivative <strong>of</strong> a function, f. Find:<br />

a. any critical numbers.<br />

b. any intervals where the function is increasing/decreasing.<br />

5 4<br />

Example 4: Let f ( x)<br />

= x − x , find:<br />

a. any critical numbers.<br />

b. any intervals where the function is increasing/decreasing.<br />

Lesson 12 – Curve Analysis (Polynomials) 3


To find the intervals on which a given polynomial function is increasing/decreasing using<br />

GGB:<br />

1. Use GGB to graph the derivative <strong>of</strong> the function.<br />

′ = ;<br />

2. Find any critical numbers. (Recall that the critical numbers occur whenever f ( x) 0<br />

hence, simply find the zeros <strong>of</strong> f ′ .)<br />

2. Create a number line, subdividing the line using the critical numbers.<br />

3. Use the graph <strong>of</strong> the derivative (or compute the value <strong>of</strong> a test point) to determine the sign<br />

(positive or negative) <strong>of</strong> the y values <strong>of</strong> the derivative in each interval and record this on your<br />

number line.<br />

4. In each interval in which the derivative is positive, the function is increasing. In each interval<br />

in which the derivative is negative, the function is decreasing.<br />

5 2<br />

Example 5: Let f ( x) = x − 16x + 4x<br />

. Using GGB find:<br />

a. any critical numbers.<br />

Command:<br />

Answer:<br />

b. any intervals where the function is increasing/decreasing.<br />

Relative Extrema<br />

The relative extrema are the high points and the low points <strong>of</strong> a function. A relative maximum<br />

is higher than all <strong>of</strong> the points near it; a relative minimum is lower than all <strong>of</strong> the points near it.<br />

A relative maximum or a relative minimum can only occur at a critical number.<br />

Lesson 12 – Curve Analysis (Polynomials) 4


You can use the same number line that you created to determine intervals <strong>of</strong> increase/decrease to<br />

find the x coordinate <strong>of</strong> any relative extrema. Use these three statements to determine if a critical<br />

number generates a relative extremum. Once you find that x = c generates a relative extremum,<br />

you can find the y coordinate <strong>of</strong> the relative extremum by computing f ( c ) or for a more<br />

accurate answer use the extremum command in GGB.<br />

1. If the sign <strong>of</strong> the derivative changes from positive to negative at a critical number, x = c , then<br />

c,<br />

f c .<br />

the function has a relative maximum at the point ( ( ))<br />

2. If the sign <strong>of</strong> the derivative changes from negative to positive at a critical number, x = c , then<br />

c,<br />

f c .<br />

the function has a relative minimum at the point ( ( ))<br />

3. If the sign <strong>of</strong> the derivative does not change sign at a critical number, x = c , then the function<br />

c,<br />

f c .<br />

has neither a relative maximum nor a relative minimum at the point ( ( ))<br />

Example 6: Find any relative maximum and relative minimum for<br />

5 4<br />

= − .<br />

f ( x)<br />

x x<br />

Example 7: Find any relative extrema:<br />

Command:<br />

f x = x + x +<br />

Answer:<br />

6<br />

( ) 0.25 4<br />

Lesson 12 – Curve Analysis (Polynomials) 5


Concavity<br />

In business, for example, the first derivative might tell us that our sales are increasing, but the<br />

second derivative will tell us if the pace <strong>of</strong> the increase is increasing or decreasing.<br />

From these graphs, you can see that the shape <strong>of</strong> the curve change differs depending on whether<br />

the slopes <strong>of</strong> tangent lines are increasing or decreasing. This is the idea <strong>of</strong> concavity.<br />

Example 8: The graph given below is the graph <strong>of</strong> a function f. Determine the interval(s) on<br />

which the function is concave upward and the interval(s) on which the function is concave<br />

downward.<br />

We find concavity intervals by analyzing the second derivative <strong>of</strong> the function. The analysis is<br />

very similar to the method we used to find increasing/decreasing intervals.<br />

1. Use GeoGebra to graph the second derivative <strong>of</strong> the function. Then find the zero(s) <strong>of</strong> the<br />

second derivative.<br />

2. Create a number line and subdivide it using the zeros <strong>of</strong> the second derivative.<br />

3. Use the graph <strong>of</strong> the second derivative to determine the sign (positive or negative) <strong>of</strong> the y<br />

values <strong>of</strong> the second derivative in each interval and record this on your number line.<br />

4. In each interval in which the second derivative is positive, the function is concave upward. In<br />

each interval in which the second derivative is negative, the function is concave downward.<br />

Lesson 12 – Curve Analysis (Polynomials) 6


Example 9: State intervals on which the function is concave upward and intervals on which the<br />

1 5 2 2<br />

function is concave downward: f ( x) = x − x −8x<br />

− 1<br />

2 3<br />

Command:<br />

You’ll also need to be able to identify the point(s) where concavity changes. A point where<br />

concavity changes is called a point <strong>of</strong> inflection.<br />

You can use the same number line that you created to determine concavity intervals to find the x<br />

coordinate <strong>of</strong> any inflection points. Use the following two statements to determine if a zero <strong>of</strong><br />

the second derivative generates an inflection point.<br />

1. If the sign <strong>of</strong> the second derivative changes from positive to negative or from negative to<br />

positive at a number, x c<br />

c,<br />

f c .<br />

= , then the function has an inflection point at the point ( ( ))<br />

2. If the sign <strong>of</strong> the second derivative does not change sign at a number, x = c , then the function<br />

c,<br />

f c .<br />

does not have an inflection point at the point ( ( ))<br />

Once you find that x = c generates an inflection point, you can find the y coordinate <strong>of</strong> the<br />

inflection point by computing f ( c ).<br />

Example 10: Given<br />

1 5 2 2<br />

f ( x) = x − x −8x<br />

− 1, find any inflection points.<br />

2 3<br />

Example 11: Given<br />

Command:<br />

3 2<br />

f ( x)<br />

= x − 3x<br />

− 24x<br />

+ 32 , find any inflection points.<br />

Answer:<br />

Lesson 12 – Curve Analysis (Polynomials) 7

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