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Disintegration theory for von Neumann algebras

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2.4 Decomposable <strong>von</strong> <strong>Neumann</strong> <strong>algebras</strong><br />

be a separable, strong operator dense C ∗ -algebra in M. That this is always the case is the proved in<br />

Proposition 2.30 and is interesting in its own right. The other is that the decomposition of M might<br />

depend on the choice of the subalgebra A. Lemma 2.31 takes care of this.<br />

Lemma 2.29. If ϕ : M → N is a ∗ -isomorphism between <strong>von</strong> <strong>Neumann</strong> <strong>algebras</strong>, and A is a<br />

strong operator dense, norm separable C ∗ -subalgebra of M, then ϕ(A) is a strong operator dense,<br />

separable C ∗ -subalgebra of N.<br />

Proof. The lemma is a consequence Kaplansky’s density theorem and the fact that ∗ -isomorphisms<br />

are strong operator continuous on bounded sets. Details are left to the reader.<br />

□<br />

Proposition 2.30. A <strong>von</strong> <strong>Neumann</strong> algebra M acting on a separable Hilbert space H has a strong<br />

operator dense, norm separable C ∗ -subalgebra.<br />

Proof. Let ι : M → B(H) denote the identity representation, and let {x n } be a countable, dense<br />

subset of H consisting of non-zero vectors. The inflation of ι, ι (∞) = ⊕ ∞<br />

n=1<br />

ι is a faithful representation<br />

of M on the separable Hilbert space ⊕ ∞<br />

n=1 H, and the image ι(∞) (M) has a separating vector,<br />

(||x 1 || −1 x 1 , ||x 2 || −2 x 2 , . . .). Thus, by the previous lemma we may assume that M has a separating<br />

vector.<br />

Then every normal functional on M is of the <strong>for</strong>m T ↦→ ω x,y (T) = 〈T x, y〉 (see <strong>for</strong> instance Theorem<br />

7.3.3 in [K&R II]). In the following ||ω x,y || denotes the norm of the functional viewed as a functional<br />

on M (as opposed to a functional on all of B(H)). For each m, n ∈ N choose A mn in (M) 1 such that<br />

ω xm ,x m<br />

(A mn ) ≥ ||ω xm ,x n<br />

|| − 1 4 , and let A be the C∗ -algebra generated by {A mn }. Notice that A is norm<br />

separable. We prove that A is strong operator dense in M.<br />

Suppose ||ω x,y |A|| = 0, but ||ω x,y || = 1 <strong>for</strong> some x, y ∈ H. Let ε > 0 be given, and choose x m , x n such<br />

that ||x m − x|| and ||x n − y|| are less that ε. Then <strong>for</strong> ||T|| ≤ 1<br />

|ω x,y (T) − ω xm ,x n<br />

(T)| = |〈T x, y〉 − 〈T x m , x n 〉|<br />

= |〈T x, y − x n 〉 + 〈T(x − x m ), x n 〉|<br />

≤ ||T|| ||x|| ||y − x n || + ||T|| ||x − x m || ||x n ||<br />

≤<br />

(||x|| + ||y|| + ε)ε.<br />

So if we let ε be such that (||x|| + ||y|| + ε)ε < 1 4 , then ||ω x,y − ω xm ,x n<br />

|| < 1 4 .<br />

But also<br />

||ω x,y − ω xm ,x n<br />

|| ≥ |(ω x,y − ω xm ,x n<br />

)(A mn )| = ω xm ,x n<br />

(A mn )<br />

≥ ||ω xm ,x n<br />

|| − 1 4 ≥ ||ω x,y|| − 1 2 = 1 2 .<br />

This gives a contradiction, and so each normal functional annihilating A also annihilates M.<br />

Since the normal functionals are the ultraweakly continuous functionals, we get by the Hahn-Banach<br />

theorem ([K&R I] theorem 1.2.13), that the closure of A in the ultraweak topology is M.<br />

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