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passive and active compensations for current transformers - Agir

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PASSIVE AND ACTIVE COMPENSATIONS FOR CURRENT TRANSFORMERS<br />

Fig. 14. Active<br />

compensation<br />

schematic.<br />

Fig. 16. Experimental rig.<br />

Using SPICE simulation of the electronic circuit<br />

in Figure 14, angle error results are presented in<br />

Figure 15.a <strong>for</strong> nominal <strong>current</strong> I 1n <strong>and</strong> Figure 15.b<br />

<strong>for</strong> a <strong>current</strong> as low as 5% I 1n .<br />

The following wave<strong>for</strong>ms were acquired using<br />

an acquisition system based on a HP- digital<br />

sampling oscilloscope, <strong>and</strong> prove predicted results<br />

into the DSO error limits. An example of input/output<br />

<strong>current</strong>s is illustrated on the DSO – Figure 17.<br />

Fig. 17. Input <strong>and</strong> output wave<strong>for</strong>ms<br />

acquired by the DSO.<br />

a) Θ =0,00736°<br />

In practice low <strong>current</strong>s, with respect to I 1n ,<br />

errors behavior is important, that this domain was<br />

extensively explored. The following results are<br />

obtained <strong>for</strong> a primary <strong>current</strong> of 20%I 1n . In<br />

Figure 18 are illustrated the wave<strong>for</strong>ms in the<br />

actual case of a burden reduced with 50%, <strong>and</strong> in<br />

Figure 19 are the correspondent results <strong>for</strong> a burden<br />

increased ten times. No actual differences may be<br />

observed in the bought limit cases <strong>for</strong> the aspect of<br />

the main wave<strong>for</strong>ms.<br />

b) Θ =0,00738°<br />

Fig. 15. Angle error <strong>for</strong> simulated circuit in Figure 14.<br />

5. EXPERIMENTAL ASPECTS<br />

FOR ACTIVE COMPENSATION<br />

The implemented instrument using trans<strong>for</strong>mers<br />

<strong>active</strong> compensation is illustrated in Figure 16 <strong>for</strong> a<br />

100 A/5 A ratio trans<strong>for</strong>mer <strong>and</strong> S n = 5 VA.<br />

Fig. 18. Current wave<strong>for</strong>ms in the case of I1=20%I1n,<br />

Z2=50%Z2n.<br />

METROLOGIE 4/2008 9

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