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Module 4. Refrigeration and Heat Pump Systems The Vapor ...

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Assumptions: SSSF, Negligible ∆KE <strong>and</strong> ∆PE, Single-Inlet, Single-Outlet conditions<br />

K. Nasr,c:\thermo \module<strong>4.</strong>doc<br />

Process Device 1st Law 2nd Law<br />

.<br />

.<br />

1→2: Isentropic Compression Compressor<br />

WComp . = m(h1 − h<br />

2)<br />

s 2 = s 1<br />

.<br />

.<br />

2 →3: p = C. <strong>Heat</strong> Rejection Condenser<br />

QCond.<br />

= m(h3 − h<br />

2)<br />

s 2 > s 3<br />

3 →4: Adiabatic Throttling Throttling Device h 3 = h 4 s 4 > s 3<br />

(O-Tube, TXV)<br />

.<br />

.<br />

4 →1: p = C. <strong>Heat</strong> Absorption Evaporator<br />

Q = m(h − h )<br />

s 1 > s 4<br />

COP = Q Evap . / W Comp .<br />

Evap.<br />

1 4<br />

¯<br />

Actual Cycle Operation: Deviates from ideal cycle operation by having:<br />

1. Pressure drops due to friction in connecting pipes<br />

2. <strong>Heat</strong> transfer exists across connecting pipes<br />

3. Pressure drops occur through the condenser <strong>and</strong> evaporator tubes<br />

<strong>4.</strong> <strong>Heat</strong> transfer occurs from the compressor<br />

5. Frictional effects <strong>and</strong> flow separation occur on the compressor blades<br />

6. Refrigerant vapor entering the compressor may be slightly superheated<br />

7. Refrigerant temperature exiting the condenser may be slightly below saturation.<br />

A desirable effect out of the above list is item 7. Having a subcooled liquid exiting the<br />

condenser results in having a larger refrigeration effect.<br />

Problem:<br />

A vapor-compression refrigeration system for a household refrigerator has a refrigerating capacity of<br />

1000 Btu/h. <strong>The</strong> refrigerant, R134a, enters the evaporator at –10 °F <strong>and</strong> exits at 0 °F. <strong>The</strong> isentropic<br />

compressor efficiency is 80%. <strong>The</strong> refrigerant condenses at 95 °F <strong>and</strong> exits the condenser subcooled<br />

at 90 °F. <strong>The</strong>re are no significant pressure drops in the flows through the evaporator <strong>and</strong> condenser.<br />

We want to determine the evaporator <strong>and</strong> condenser pressures, the mass flow rate of the refrigerant,<br />

the compressor power input, <strong>and</strong> the coefficient of performance.<br />

Solution:<br />

• First, the refrigerating capacity is the rate of heat transfer into the refrigerant flowing in the<br />

evaporator. It is the cooling effect, that is the rate of heat transfer extracted from air on the outside<br />

of the evaporator. <strong>The</strong> refrigerating capacity is normally given in tons of refrigeration for a system<br />

where one ton of refrigeration is equivalent to 12000 Btu/hr.<br />

• Second, since the inlet to the evaporator is always a mixture of liquid <strong>and</strong> vapor, the pressure<br />

therefore is the saturation pressure at the given temperature. It is also assumed that frictional effects,<br />

between the refrigerant <strong>and</strong> the tubes of the evaporator, are neglected so that the pressure at the<br />

inlet equals the pressure at the exit of the evaporator.<br />

Copyright © 2004, K. Nasr. All Rights Reserved Page 3

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