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March 3, 2008 Objectives: define molarity and practice calculating ...

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<strong>March</strong> 3, <strong>2008</strong><br />

<strong>Objectives</strong>:<br />

­ <strong>define</strong> <strong>molarity</strong> <strong>and</strong> <strong>practice</strong> <strong>calculating</strong> concentrations<br />

Molarity ­ amount of solute dissolved per liter of solvent (mols/L = M)<br />

Solute ­ substance being dissolved (sugar into water)<br />

Solvent ­ dissolving agent (most of the time ­ water)<br />

Types of Problems<br />

1. From Dilution ­ M 1 V 1 = M 2 V 2<br />

Example ­ How much 12.0 M HCl would be needed to make 3.0 L of 0.50<br />

M HCl?<br />

2. From Mass<br />

Example ­ What is the <strong>molarity</strong> of 34.5 g of silver chloride dissolved in 3.0 L<br />

of water?<br />

1


3. Calculating the number of moles per ion<br />

Example ­ How many moles of each ion are present in 1.25 L of<br />

0.250 M Na 3 PO 4 solution?<br />

4. Stoichiometry of Solution Reactions<br />

Example ­ One way to determine the amount of chloride ion in a water<br />

sample is to titrate the sample with st<strong>and</strong>ard AgNO 3 solution to produce<br />

solid AgCl according to this reaction: Ag + (aq) + Cl ­ (aq) AgCl (s)<br />

If a 25.0 mL water sample requires 27.2 mL of 0.104 M AgNO 3 in such a<br />

titration, what is the concentration of Cl ­ in the sample?<br />

2

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