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Synchronous Motors

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esistance combines with synchronous reactance and gives the<br />

synchronous impedance of the machine.<br />

(ii) The second effect is that a voltage is generated in the stator winding by<br />

the synchronously-revolving field of the rotor as shown in Fig. (11.5 (i)).<br />

This generated e.m.f. E B is known as back e.m.f. and opposes the stator<br />

voltage V. The magnitude of E b depends upon rotor speed and rotor flux<br />

φ per pole. Since rotor speed is constant; the value of E b depends upon<br />

the rotor flux per pole i.e. exciting rotor current I f .<br />

Fig. (11.5 (i)) shows the schematic diagram for one phase of a star-connected<br />

synchronous motor while Fig. (11.5 (ii)) shows its equivalent circuit. Referring<br />

to the equivalent circuit in Fig. (11.5 (ii)).<br />

Net voltage/phase in stator winding is<br />

E r = V − E b<br />

Armature current/phase,<br />

E<br />

I a =<br />

Z<br />

r<br />

s<br />

phasor difference<br />

where<br />

s<br />

2<br />

a<br />

Z = R + X<br />

2<br />

s<br />

This equivalent circuit helps considerably in understanding the operation of a<br />

synchronous motor.<br />

A synchronous motor is said to be normally excited if the field excitation is such<br />

that E b = V. If the field excitation is such that E b < V, the motor is said to be<br />

under-excited. The motor is said to be over-excited if the field excitation is such<br />

that E b > V. As we shall see, for both normal and under excitation, the motor has<br />

lagging power factor. However, for over-excitation, the motor has leading power<br />

factor.<br />

Note: In a synchronous motor, the value of X s is 10 to 100 times greater than R a .<br />

Consequently, we can neglect R a unless we are interested in efficiency or<br />

heating effects.<br />

11.6 Motor on Load<br />

In d.c. motors and induction motors, an addition of load causes the motor speed<br />

to decrease. The decrease in speed reduces the counter e.m.f. enough so that<br />

additional current is drawn from the source to carry the increased load at a<br />

reduced speed. This action cannot take place in a synchronous motor because it<br />

runs at a constant speed (i.e., synchronous speed) at all loads.<br />

What happens when we apply mechanical load to a synchronous motor? The<br />

rotor poles fall slightly behind the stator poles while continuing to run at<br />

298

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