Chapter 3 : Reservoir models - KU Leuven
Chapter 3 : Reservoir models - KU Leuven
Chapter 3 : Reservoir models - KU Leuven
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If the concentration time is not taken into account as a variable parameter with<br />
the runoff, the extra variation in smoothing and peak shift can be modelled using<br />
the dynamic storage. In that way the smoothing module and the dynamic storage<br />
module overlap to some extent, although they cannot replace each other completely.<br />
The differential equation that describes a linear static reservoir model is :<br />
dV<br />
dt<br />
= Q − Q<br />
(3.8)<br />
in<br />
through<br />
with :<br />
Q<br />
through<br />
V<br />
=<br />
V<br />
Q m<br />
(3.9)<br />
m<br />
In this set of equations, V is the instantaneous storage volume in the reservoir,<br />
V m the maximum storage, Q in the inflow, Q m the maximum throughflow and<br />
Q out the instantaneous throughflow. The analytical solution for this set of equations<br />
at time t+dt as a function of the instantaneous storage V t in the previous time step t is :<br />
V Q V ⎛<br />
m<br />
Qm<br />
Q<br />
V dt V Qm<br />
t+ dt = in − ⎛ ⎞⎞<br />
⎜−<br />
⎟<br />
⎜<br />
t<br />
V<br />
dt<br />
m ⎝ ⎝ m ⎠<br />
⎟<br />
+ ⎛ ⎞<br />
1 exp exp ⎜−<br />
⎟ (3.10)<br />
⎠<br />
⎝ m ⎠<br />
When the maximum storage V m is reached, the overflow starts spilling and the overflow<br />
discharge is equal to the difference between inflow Q in and maximum throughflow Q m .<br />
The reservoir modelling system Remuli however uses piecewise linear relationships for<br />
the storage/throughflow relationships, which also makes the inclusion of extra storage<br />
during the overflow event possible (see paragraph 3.3.2).<br />
The dynamic storage and the static storage are fitted together as shown in figure 3.15<br />
using the following equations :<br />
Vm<br />
V k Q k Q<br />
Q Q Vdm<br />
= stat through + dyn in = through +<br />
Q<br />
Q in<br />
(3.11)<br />
in which V dm is the maximum dynamic storage corresponding with the maximum<br />
inflow Q dm .<br />
Combined with the continuity equation this leads to :<br />
Or solved :<br />
dV<br />
dt<br />
⎛ Vdm<br />
V<br />
Vt+ dt = Qin<br />
⎜ +<br />
⎝ Q Q<br />
dm<br />
⎛ Vdm<br />
Qm<br />
⎞ Qm<br />
= Qin<br />
⎜1 + ⎟ −<br />
⎝ Q V ⎠ V<br />
V<br />
(3.12)<br />
m<br />
m<br />
dm<br />
m<br />
m<br />
m<br />
⎞ ⎛ Qm<br />
V dt V Qm<br />
⎟ − ⎛ ⎞⎞<br />
⎜−<br />
⎟<br />
t<br />
⎠<br />
⎜<br />
⎝<br />
V<br />
dt<br />
⎝<br />
m ⎠<br />
⎟ + ⎛ − ⎞<br />
1 exp exp ⎜ ⎟ (3.13)<br />
⎠ ⎝ m ⎠<br />
dm<br />
<strong>Chapter</strong> 3 : <strong>Reservoir</strong> <strong>models</strong> 3.29