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Three types of binary stars.

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<strong>Three</strong> <strong>types</strong> <strong>of</strong> <strong>binary</strong> <strong>stars</strong>.<br />

• Visual binaries – Stars that are far enough<br />

apart that they can be seen as separate <strong>stars</strong><br />

through a telescope. They typically have orbital<br />

periods that are hundreds <strong>of</strong> years long.


Stars orbit a common center <strong>of</strong> mass. More<br />

massive star has smaller orbit.


• Spectroscopic Binaries – Much shorter orbital<br />

periods because <strong>stars</strong> are so close to each<br />

other that they aren’t separable. But the<br />

spectral lines show that there are two <strong>stars</strong>.


A Dilemma<br />

• Spectroscopic binaries <strong>of</strong>ten show double the<br />

absorption lines <strong>of</strong> a regular spectrum. But the<br />

wavelength at which a line forms does not<br />

depend on the type <strong>of</strong> star. It is set by the<br />

element that is giving <strong>of</strong>f the light. Why don’t<br />

the two absorption lines fall right on top <strong>of</strong> each<br />

other?


A Dilemma<br />

• Spectroscopic binaries <strong>of</strong>ten show double the<br />

absorption lines <strong>of</strong> a regular spectrum. But the<br />

wavelength at which a line forms does not<br />

depend on the type <strong>of</strong> star. It is set by the<br />

element that is giving <strong>of</strong>f the light. Why don’t<br />

the two absorption lines fall right on top <strong>of</strong> each<br />

other?<br />

• The reason is the Doppler Shift.


The Doppler shift is a wave phenomenon<br />

• When an object emits a wave, the wave moves<br />

out in all directions with its center at the source.<br />

• This is true <strong>of</strong> water waves, sound waves, and<br />

light waves.


What if the source is moving?<br />

• If a source <strong>of</strong> the wave is moving, then as the<br />

source emits the wave, the center is<br />

continuously moving.


Here is a real picture <strong>of</strong> Doppler shift


When a star is moving toward or away from<br />

us Doppler shift is blue-ward (toward) or redward<br />

(away) <strong>of</strong> what it would be if the star<br />

was not moving.


We can see this as a shift in the absorption or emission<br />

lines in a spectrum. The wavelength that absorption<br />

occurs at depends only on the type <strong>of</strong> atom. But the shift<br />

depends on the motion


• Using the Doppler shift <strong>of</strong> light from a star we<br />

can not only tell if the star is coming toward us<br />

or going away from us, but we can also<br />

measure the speed at which it is moving toward<br />

or away.


How is the velocity related to the<br />

amount <strong>of</strong> Doppler shift?<br />

1. The faster the object is<br />

moving toward or away from<br />

us the bigger the shift should<br />

be.<br />

2. The faster the object moves<br />

toward or away from us the<br />

smaller the shift will be.<br />

3. If an object is moving rapidly<br />

towards us we get a large<br />

speed, but if it is moving<br />

rapidly away we get a small<br />

speed.


Relation <strong>of</strong> velocity to Doppler shift<br />

• The bigger the shift the fast the velocity<br />

because the center <strong>of</strong> the wave is moving<br />

rapidly causing greater compression or<br />

expansion.<br />

• v/c = Δλ/λ o<br />

• where v is the velocity, c is the speed <strong>of</strong> light,<br />

λ o is the rest wavelength and Δλ is the doppler<br />

shift. Δλ = (λ observed – λ o )


What about <strong>stars</strong> orbiting each<br />

other?<br />

• The result is two absorption lines that have slightly<br />

different wavelengths from what they have in the lab.


Binary star simulator<br />

• http://astro.ph.unimelb.edu.au/s<strong>of</strong>tware/<strong>binary</strong>/<strong>binary</strong>.htm


What will happen if I put the two <strong>stars</strong> closer<br />

together?<br />

1. They will speed up<br />

2. They will slow down<br />

3. They will remain at<br />

the same speed


What did we find out?<br />

• When the <strong>stars</strong> are farther apart (a is increased)<br />

they move more slowly in their orbit.


How can we find the orbital period for<br />

spectroscopic binaries?<br />

1. Watch the <strong>stars</strong> orbit each<br />

other and see how long it<br />

takes<br />

2. Watch for the absorption<br />

lines to return to their original<br />

wavelength<br />

3. Measure the masses and<br />

compute the period


What did we find out?<br />

• When the <strong>stars</strong> are farther apart (a is increased)<br />

they move more slowly in their orbit.<br />

• Measuring the time it takes for the spectral lines<br />

to return to their starting wavelength gives us<br />

the orbital period


What will happen I make Star #1 mass three<br />

times Star #2 mass?<br />

1. Star #2 will have a<br />

bigger orbit than Star #1<br />

2. Star #2 will a smaller<br />

orbit than Star #1<br />

3. The orbits will not<br />

change


What did we find out?<br />

• When the <strong>stars</strong> are farther apart (a is increased) they<br />

move more slowly in their orbit.<br />

• Measuring the time it takes for the spectral lines to<br />

return to their starting wavelength gives us the orbital<br />

period<br />

• When the mass <strong>of</strong> one star is increased the other star<br />

orbits at a greater distance.


If Star #2 is orbiting 3 times faster than Star #1,<br />

what does that tell you about their masses?<br />

1. M 1 = 3M 2<br />

2. M 1 = M 2 /3<br />

3. M 1 = M 2


What did we find out?<br />

• When the <strong>stars</strong> are farther apart (a is increased) they<br />

move more slowly in their orbit.<br />

• Measuring the time it takes for the spectral lines to<br />

return to their starting wavelength gives us the orbital<br />

period<br />

• When the mass <strong>of</strong> one star is increased the other star<br />

orbits at a greater distance.<br />

• If M 1 = 3M 2 then star #2 will orbit 3 times faster than<br />

star #1


Let’s look at Kepler’s Law<br />

• (M 1 + M 2 )P 2 = (4π 2 /G)a 3<br />

• So we have the relative masses<br />

• We have the period.<br />

• We just need a 3 .<br />

• But v orbital = 2πa/P or a = v orbital *P/2π<br />

• So how do we find v orbital ?


How can we get the orbital velocity <strong>of</strong> the <strong>stars</strong>?<br />

1. Measure the Doppler shift for<br />

any spectroscopic <strong>binary</strong> pair<br />

2. Use the peak radial velocity<br />

from the velocity plot to get<br />

the orbital velocity.<br />

3. Find binaries which are<br />

eclipsing, because we are<br />

then in the orbital plane and<br />

can determine v orbital


Eclipsing Binaries


• If the <strong>binary</strong> <strong>stars</strong> are eclipsing, then it is<br />

guaranteed that we are in the orbital plane.<br />

• This means that the maximum radial velocity on<br />

the velocity plot gives us the orbital velocity.<br />

• Now we have “a” and we have “P”. We can get<br />

rid <strong>of</strong> one <strong>of</strong> the “M”s because we know how<br />

they are related.


Example<br />

• (M 1 + M 2 )P 2 = (4π 2 /G)a 3<br />

• If M 1 = 3M 2 then we can write:<br />

• (3M 2 + M 2 )P 2 = (4π 2 /G)a 3<br />

• (4M 2 ) = (4π 2 /G)(a 3 /P 2 )<br />

• Once we find M 2 we know that M 1 is three times<br />

the mass


Masses <strong>of</strong> Stars<br />

• Many such measurements show us that mass<br />

increases on the Main Sequence as the temperature<br />

and luminosity increase. As theory predicts.<br />

• Furthermore, Mass does not correlate with luminosity<br />

for giant, evolved <strong>stars</strong>. Giants might have a large<br />

mass, or they might have a small mass, but still they<br />

are very luminous.<br />

• Also the mass <strong>of</strong> a white dwarf is not correlated to its<br />

luminosity.<br />

• Something different is happening for these guys.

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