22.05.2014 Views

Fluids in Motion Supplement I

Fluids in Motion Supplement I

Fluids in Motion Supplement I

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Fluid Drag at Low Reynolds Number<br />

For very low Reynolds Number (Re < 0.1 – this regime is called creep<strong>in</strong>g flow), the drag<br />

coefficient for a sphere has been shown to be:<br />

C<br />

d<br />

=<br />

24<br />

Re<br />

where Re is the Reynolds Number = Dvρ/η. Plugg<strong>in</strong>g this <strong>in</strong>to the drag equation on the previous<br />

page, and us<strong>in</strong>g the cross-sectional area of a sphere<br />

⎛1 2⎞ 2⎛1 2⎞<br />

24<br />

Fd<br />

= A⎜ ρv ⎟Cd<br />

= πR ⎜ ρv<br />

⎟<br />

⎝2 ⎠ ⎝2 ⎠ 2 /<br />

(note that D = 2R has been used here). There is a lot of cancellation and we get the f<strong>in</strong>al<br />

expression for the Stokes drag, or drag on a sphere at very low Reynolds Number:<br />

Fd<br />

= 6πη<br />

Rv<br />

This expression was calculated by Stokes <strong>in</strong> 1850 for the drag force on a sphere of radius R<br />

mov<strong>in</strong>g with speed v relative to a medium with viscosity η. This expression only applies to a<br />

sphere, but other shapes have drag forces that have similar forms at low Reynolds Number.<br />

Objects with densities ρ 1 that differ from the density, ρ 2 , of the surround<strong>in</strong>g medium will either<br />

s<strong>in</strong>k (if ρ 1 more dense than ρ 2 ) or float (if ρ 1 less dense than ρ 2 ).<br />

For objects sediment<strong>in</strong>g <strong>in</strong> fluids three forces act<strong>in</strong>g on the particle:<br />

– Gravity, F g = mg = ρ 1 Vg<br />

– Buoyant force, F b = m fluid displaced g = ρ 2 Vg<br />

– Hydrodynamic drag, F d<br />

( Rvρ η)<br />

Sedimentation and Term<strong>in</strong>al Velocity<br />

The drag force <strong>in</strong>creases with speed and so if a particle starts at rest, it will accelerate until the<br />

drag force equals the sum of the gravitational and buoyant forces. At this po<strong>in</strong>t the object will<br />

move with a constant velocity. Choos<strong>in</strong>g down to be negative, the force balance is then:<br />

∑ Fy = Fd + Fb − Fg<br />

= 0 F d F b<br />

Plugg<strong>in</strong>g <strong>in</strong> for F g and F b , we get:<br />

F + ρ gV − ρ gV =<br />

d<br />

2 1<br />

0<br />

ρ 1<br />

ρ 2<br />

We can rearrange to get the fluid drag at term<strong>in</strong>al velocity is given by:<br />

Fd<br />

( ρ ρ )<br />

= −<br />

1 2<br />

gV<br />

F g

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!