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STATISTICS 512 TECHNIQUES OF MATHEMATICS FOR ...

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20<br />

interpretation of “spanning” and “independence”<br />

in are, in terms of X,<br />

spanning: Xc = y is solvable (in c) foranyy ∈ ;<br />

independence: y = 0 in the above ⇒ c = 0.<br />

If instead we begin with a matrix X, then the set<br />

of all linear combinations of the columns of X is<br />

a vector space (why?), called the column space<br />

((X)), whose dimension is called the rank of<br />

X. The independent columns of X form a basis<br />

for (X).<br />

Results about matrix ranks:<br />

1) (AB) ≤ (A): Since (AB) ⊆ (A)<br />

(why?),<br />

(AB) =dim((AB)) ≤ dim((A)) = (A)<br />

(The inequality follows — ass’t 1 — from Fact<br />

2above.)<br />

2) The rank of a matrix is at least as large as that<br />

of any of its submatrices (you should formulate<br />

and prove this).

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