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Analysis of Markov chain algorithms on spanning trees, rooted ...

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J. Fehrenbach and L. Rüschendorf 9<br />

So f XY<br />

satisfies equati<strong>on</strong> (3.1). We show now how to select for v ∈ D the pair<br />

X v , Y v and how to derive from the paths in P XvYv<br />

the paths <str<strong>on</strong>g>of</str<strong>on</strong>g> P XY<br />

.<br />

If d min = 2 let a ∈ X and b ∈ Y be the two edges in M at this node<br />

v and set X v := (X \ {a}) ∪ {b} and Y v := Y . For this pair the inducti<strong>on</strong><br />

hypothesis holds because M v := (V, X v ∪ Y v )/(X v ∩ Y v ) = (M/b) \ {a} has<br />

exactly l nodes. A path p ′ = (B i) ′ 0≤i

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