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Sigma notation - Mathcentre

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Exercises<br />

1. Write out what is meant by<br />

(a)<br />

(e)<br />

5∑<br />

n=1<br />

N∑<br />

n 3<br />

x 2 i<br />

i=1<br />

(b)<br />

(f)<br />

5∑<br />

3 n (c)<br />

n=1<br />

N∑<br />

f i x i<br />

i=1<br />

4∑<br />

(−1) r r 2<br />

r=1<br />

(d)<br />

4∑<br />

k=1<br />

(−1) k+1<br />

2k + 1<br />

2. Evaluate<br />

4∑<br />

k 2 .<br />

k=1<br />

2. Some examples<br />

Example<br />

4∑<br />

Evaluate r 3 .<br />

Solution<br />

r=1<br />

This is the sum of all the r 3 terms from r = 1 to r = 4. So we take each value of r, work out r 3<br />

in each case, and add the results. Therefore<br />

Example<br />

5∑<br />

Evaluate n 2 .<br />

Solution<br />

n=2<br />

4∑<br />

r 3 = 1 3 + 2 3 + 3 3 + 4 3<br />

r=1<br />

= 1 + 8 + 27 + 64<br />

= 100 .<br />

In this example we have used the letter n to represent the variable in the sum, rather than r.<br />

Any letter can be used, and we find the answer in the same way as before:<br />

Example<br />

5∑<br />

Evaluate 2 k .<br />

k=0<br />

5∑<br />

n 2 = 2 2 + 3 2 + 4 2 + 5 2<br />

n=2<br />

= 4 + 9 + 16 + 25<br />

= 54 .<br />

3 c○ mathcentre July 18, 2005

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