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Sigma notation - Mathcentre

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Key Point<br />

If a and c are constants, and if f(k) and g(k) are functions of k, then<br />

n∑<br />

c = nc ,<br />

k=1<br />

n∑<br />

ck = c<br />

k=1 k=1<br />

n∑<br />

k ,<br />

n∑<br />

(k + c) = nc +<br />

k=1<br />

n∑<br />

(ag(k) + c) = nc + a<br />

k=1<br />

n∑<br />

(f(k) + g(k)) =<br />

n∑<br />

k ,<br />

k=1<br />

n∑<br />

g(k) ,<br />

k=1<br />

n∑<br />

f(k) +<br />

k=1<br />

k=1 k=1<br />

n∑<br />

g(k) .<br />

We shall finish by taking a particular example and using sigma <strong>notation</strong>. Suppose that we want<br />

to find the mean of a set of examination marks. Now<br />

total sum of marks<br />

mean =<br />

no. of values<br />

So if the marks were 2, 3, 4, 5 and 6 we would have<br />

mean = 2 + 3 + 4 + 5 + 6 = 20 5 5<br />

But more generally, if we have a set of marks x i , where i runs from 1 to n, we can write the<br />

mean using sigma <strong>notation</strong>. We write<br />

mean = 1 n∑<br />

x i .<br />

n<br />

Exercises<br />

i=1<br />

4. By writing out the terms explicitly, show that<br />

5∑ 5∑<br />

6∑ 6∑<br />

(a) 3k = 3 k (b) 4i 2 = 4 i 2<br />

(d)<br />

k=1<br />

8∑<br />

c = 8c.<br />

k=1<br />

k=1<br />

i=1 i=1<br />

(c)<br />

4∑<br />

5 = 4 × 5 = 20<br />

n=1<br />

5. Write out what is meant by<br />

4∑<br />

k=1<br />

1<br />

(2k + 1)(2k + 3) .<br />

9 c○ mathcentre July 18, 2005

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