Sigma notation - Mathcentre
Sigma notation - Mathcentre
Sigma notation - Mathcentre
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Key Point<br />
If a and c are constants, and if f(k) and g(k) are functions of k, then<br />
n∑<br />
c = nc ,<br />
k=1<br />
n∑<br />
ck = c<br />
k=1 k=1<br />
n∑<br />
k ,<br />
n∑<br />
(k + c) = nc +<br />
k=1<br />
n∑<br />
(ag(k) + c) = nc + a<br />
k=1<br />
n∑<br />
(f(k) + g(k)) =<br />
n∑<br />
k ,<br />
k=1<br />
n∑<br />
g(k) ,<br />
k=1<br />
n∑<br />
f(k) +<br />
k=1<br />
k=1 k=1<br />
n∑<br />
g(k) .<br />
We shall finish by taking a particular example and using sigma <strong>notation</strong>. Suppose that we want<br />
to find the mean of a set of examination marks. Now<br />
total sum of marks<br />
mean =<br />
no. of values<br />
So if the marks were 2, 3, 4, 5 and 6 we would have<br />
mean = 2 + 3 + 4 + 5 + 6 = 20 5 5<br />
But more generally, if we have a set of marks x i , where i runs from 1 to n, we can write the<br />
mean using sigma <strong>notation</strong>. We write<br />
mean = 1 n∑<br />
x i .<br />
n<br />
Exercises<br />
i=1<br />
4. By writing out the terms explicitly, show that<br />
5∑ 5∑<br />
6∑ 6∑<br />
(a) 3k = 3 k (b) 4i 2 = 4 i 2<br />
(d)<br />
k=1<br />
8∑<br />
c = 8c.<br />
k=1<br />
k=1<br />
i=1 i=1<br />
(c)<br />
4∑<br />
5 = 4 × 5 = 20<br />
n=1<br />
5. Write out what is meant by<br />
4∑<br />
k=1<br />
1<br />
(2k + 1)(2k + 3) .<br />
9 c○ mathcentre July 18, 2005