Core Maths C1 Revision Notes - Mr Barton Maths
Core Maths C1 Revision Notes - Mr Barton Maths
Core Maths C1 Revision Notes - Mr Barton Maths
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1 Algebra<br />
Indices<br />
Rules of indices<br />
a m × a n = a m+n<br />
a m ÷ a n = a m–n a 0 = 1<br />
(a m ) n = a mn<br />
a –n =<br />
1<br />
n<br />
a<br />
a<br />
1<br />
n<br />
m n<br />
=<br />
n<br />
a<br />
n<br />
( )<br />
n m<br />
a = a = a<br />
m<br />
Examples:<br />
(i) 5 –3 × 5 4 = 5 –3 + 4 = 5 1 = 5.<br />
7 –4 × 7 –2 = 7 –4 + –2 = 7 –4 – 2 = 7 –6 =<br />
(ii) 3 5 ÷ 3 –2 = 3 5 – –2 = 3 5 + 2 = 3 7 .<br />
9 –4 ÷ 9 6 = 9 –4 – 6 = 9 –10 1<br />
=<br />
9 10<br />
1<br />
7 6 .<br />
11 –3 ÷ 11 –5 = 11 –3 – –5 = 11 –3 + 5 = 11 2 = 121<br />
(iii) (6 –3 ) 4 = 6 –3 × 4 = 6 –12 1<br />
=<br />
6 . 12<br />
(iv)<br />
2 1<br />
2<br />
64 3<br />
64 3 2<br />
= ⎛ ⎝ ⎜ ⎞⎟ ⎠<br />
= ( 4)<br />
= 16<br />
− 2 1<br />
(v) 125 3<br />
= since minus means turn upside down<br />
2<br />
125 3<br />
1<br />
3<br />
= , since 3 on bottom of fraction is cube root, 125 = 5<br />
2<br />
5<br />
1<br />
=<br />
25<br />
Example: (16 a ) ÷ (8 b ) = (2 4 ) a ÷ (2 3 ) b = 2 4a ÷ 2 3b = 2 4a – 3b .<br />
Example: Find x if 9 2x = 27 x + 1 .<br />
Solution: First notice that 9 = 3 2 and 27 = 3 3 and so<br />
9 2x = 27 x + 1 ⇒ (3 2 ) 2x = (3 3 ) x + 1<br />
⇒ 3 4x = 3 3x + 3<br />
⇒ 4x = 3x + 3 ⇒ x = 3.<br />
<strong>C1</strong> 14/04/2013 SDB<br />
3