Full resolution - ThePlaz.com

PRS: Stopping a Motor
Consider a motor (a loop of wire rotating in a B
field) which is driven at a constant rate by a
battery through a resistor.
Now grab the motor and prevent it from
rotating. What happens to the current in the
circuit?
0% I1:l lncreases
0% Y. Decreases
0'" 3. Remains the Same
. " v
IW, 4. I don't know lvo /
fOl
PRS: Faraday Circuit
"'kmIagnetic field B penetrates this
circuit outwards, and is increasing A
at a rate such that a current of 1 A IR=10n 'I
is induced in the circuit (which t o/' 1
direction?), ~ /
The potential difference VA-VB is: R=1 DOn
0% 1. +10 V ..,-. ~-
0% 2. ·10 V / nl'/fl
0% 3, +100V Vf!fr c>r
0% 4, -100V
0% 5, +110 V (~A ~ wV5
0% 6. ·110V
0% 7. +90V
0% B. ·90V
0% ;IS'.\. None of the above
"'"
ovl ' I
11 ,
N.l i re ( {lv5(}d c6 (~G
( l~t~ - flO fr(J~ Ch£\1l5:"j F!Jy
bdt{-Q.i'-j )v 7! lUI) Cl/(rel/[.-
)
PRS: Voltage Across Inductor
In the circuit at right the . r "Nv ",
switch is closed at t = O. A .:+:.L R I
~
voltmeter hooked across =t L
the inductor will read: E 1
0'" U> V L
= ce-,Ir f'1I
~ . 1>
v ~
L IT
- Jt
0./\ 'f ('lJ(fP;ti-
0'" 2. V L
=c(l_e- tlr )
0% 3. V L
=0
0% 4. I don't knew
Class 31
,
o CiJ((V.Ja
:l c;,{t;;/ (, ~
/,1 '( 1/0/ V~ /.It tt15f-af(,t~lI{(J v.) 1r