March 2011 - Career Point

Reaction in which benzene is formed as a product
is/are -
(A) 1, 2, 3, 4 and 5 (B) 1, 3 and 5
(C) 1 and 5 (D) 1, 2, 3 and 5
6. In a solution of an organic solute (mol. wt. = 180) in
CCl 4 , where the solute is dimerised, 50 g of the
solute are present per litre of the solution. The
osmotic pressure of the solution is 4.11 atm at 27ºC
(Assume R = 0.082 litre atm K –1 mol –1 ). The degree
of association of the solute in CCl 4 is -
(A) 75.5 % (B) 70 %
(C) 60 % (D) 80 %
7. Arrange CCl 4 , AlCl 3 , PCl 5 and SiCl 4 according to
ease of hydrolysis
(A) CCl 4 < SiCl 4 < PCl 5 < AlCl 3
(B) AlCl 3 < CCl 4 < PCl 5 < SiCl 4
(C) CCl 4 < AlCl 3 < PCl 5 < SiCl 4
(D) CCl 4 < AlCl 3 < SiCl 4 < PCl 5
8. OHC–– ––COCH 3 ⎯→
It can be performed by -
(A) glycol / H + , Zn / Hg + HCl, H 3 O +
(B) N 2 H 4 / OH – followed by H +
(C) OH – / ∆, H 2 /Ni
(D) Both (A) and (C)
OHC –– ––CH 2 CH 3
SECTION – II
Multiple Correct Answers Type
Questions 9 to 13 are multiple choice questions. Each
question has four choices (A), (B), (C) and (D), out of
which MULTIPLE (ONE OR MORE) is correct. Mark
your response in OMR sheet against the question
number of that question. + 3 marks will be given for
each correct answer and no negative marks.
9. A concentration cell is a galvanic cell is which,
(A) the electrode material and the solutions in both
half-cells are composed of the same substances
(B) only the concentrations of the two solutions
differ
(C) E ° cell = 0
(D) the Nernst equation reduces to,
⎛ 0.0591⎞
E cell = − ⎜ ⎟logQ
at 25°C
⎝ n ⎠
10
KMnO 4 + Gas (X)
H 2 O 2 + Gas (X)
Br 2 water + Gas (X)
Aq. Suspension
[Y]
H 2 SO 4
Reagent
Which of the following option (s) is/are correct
regarding (Y) among the following ?
(A) HCl (B) Conc. HNO 3
(C) O 3
(D) Excess Cl 2 water
11. XeO 3 can be prepared by
(A) XeF 2 ⎯ Hydrolysis ⎯⎯⎯→
(B) XeF 6 + SiO 2 ⎯→
(C) XeF 4 ⎯ Hydrolysis ⎯⎯⎯→
(D) XeF 6 ⎯ Hydrolysis ⎯⎯⎯→
12. Which is correct order ?
(A) Ease of hydrolysis : CH 3 COCl > CH 3 COOC 2 H 5
> (CH 3 CO) 2 O > CH 3 CONH 2
(B) Acidic strength : HCOOH > C 6 H 5 COOH
> CH 3 COOH
(C) Acidic strength : FCH 2 COOH > ClCH 2 COOH
> BrCH 2 COOH
(D) Acidic strength : 4-Methoxybenzoic acid
< Benzoic acid < 4-Nitrobenzoic acid
< 3, 4-Dinitrobenzoic acid
13. Consider the reaction sequence and pick the correct
statements
( i) NaNH2 (ii) C2H5
CH 3 –CH 2 –C≡CH ⎯⎯⎯⎯⎯⎯⎯⎯
Br →X
H2 / Pd − BaSO 4
alk. KMnO
4
⎯⎯⎯⎯⎯⎯
→ Y ⎯⎯
⎯⎯⎯
→ Z
(A) Z is a diol
(B) Z is a meso compound and is optically inactive
(C) Z is a racemic compound
(D) Y is a trans alkene
SECTION – III
Comprehension Type
This section contains 2 paragraphs; passage- I has 2
multiple choice questions (No. 14 & 15) and passage- II
has 3 multiple (No. 16 to 18). Each question has 4
choices (A), (B), (C) and (D) out of which ONLY ONE
is correct. Mark your response in OMR sheet against
the question number of that question. + 3 marks will be
given for each correct answer and – 1 mark for each
wrong answer.
Paragraph # 1 (Ques. 14 to 15)
Diprotic acid is the one, which is capable of giving 2
protons per molecule in water. Let us take a weak
diprotic acid (H 2 A) in water whose concentration is
'c' M.
H 2 A + H 2 O HA – + H 3 O +
At eq.c(1–α) cα 1 (1 – α 2 ) (cα 1 + cα 1 α 2 )
(cα1
+ cα1α
2)[cα1(1
− α2)]
Ka 1 =
c(1 − α1)
50 mL of 0.1 M H 3 PO 4 is titrated against 0.1 M
NaOH. pKa
, pK
1 a 2
and pKa 3
for H 3 PO 4 is 3, 7 and 11
respectively.
XtraEdge for IIT-JEE 51
MARCH 2011