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Chapter 10 Trigonometric functions - Ugrad.math.ubc.ca

Chapter 10 Trigonometric functions - Ugrad.math.ubc.ca

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Math <strong>10</strong>2 Notes <strong>Chapter</strong> <strong>10</strong><br />

In the expression above, the number 13 represents a shift along the time axis, and <strong>ca</strong>rries units of<br />

time. We <strong>ca</strong>n express this same function in the form<br />

( πt<br />

H(t) = 50 + 50 sin<br />

12 − 13π )<br />

.<br />

12<br />

In this version, the quantity<br />

φ = 13π<br />

12<br />

is what we have referred to as a phase shift. (This represents the point on the 2π cycle at which<br />

the function begins when we plug in t = 0.)<br />

In selecting the periodic function to use for this example, we could have made other choices.<br />

For example, the same periodic <strong>ca</strong>n be represented by any of the <strong>functions</strong> listed below:<br />

( π<br />

)<br />

H(t) = 50 − 50 sin<br />

12 (t − 1) ,<br />

( π<br />

)<br />

H(t) = 50 + 50 cos<br />

12 (t − 19) ,<br />

( π<br />

)<br />

H(t) = 50 − 50 cos<br />

12 (t − 7) .<br />

All these <strong>functions</strong> have the same values, the same amplitudes, and the same periods.<br />

Example 3: phases of the moon<br />

0 29.5<br />

Figure <strong>10</strong>.8: Periodic moon phases<br />

A cycle of waxing and waning moon takes 29.5 days approximately. Construct a periodic function<br />

to describe the changing phases, starting with a “new moon” (totally dark) and ending one cycle<br />

later.<br />

Solution:<br />

The period of the cycle is T = 29.5 days, so<br />

ω = 2π<br />

T = 2π<br />

29.5 .<br />

v.2005.1 - September 4, 2009 <strong>10</strong>

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