Chapter 10 Trigonometric functions - Ugrad.math.ubc.ca
Chapter 10 Trigonometric functions - Ugrad.math.ubc.ca
Chapter 10 Trigonometric functions - Ugrad.math.ubc.ca
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Math <strong>10</strong>2 Notes <strong>Chapter</strong> <strong>10</strong><br />
In the expression above, the number 13 represents a shift along the time axis, and <strong>ca</strong>rries units of<br />
time. We <strong>ca</strong>n express this same function in the form<br />
( πt<br />
H(t) = 50 + 50 sin<br />
12 − 13π )<br />
.<br />
12<br />
In this version, the quantity<br />
φ = 13π<br />
12<br />
is what we have referred to as a phase shift. (This represents the point on the 2π cycle at which<br />
the function begins when we plug in t = 0.)<br />
In selecting the periodic function to use for this example, we could have made other choices.<br />
For example, the same periodic <strong>ca</strong>n be represented by any of the <strong>functions</strong> listed below:<br />
( π<br />
)<br />
H(t) = 50 − 50 sin<br />
12 (t − 1) ,<br />
( π<br />
)<br />
H(t) = 50 + 50 cos<br />
12 (t − 19) ,<br />
( π<br />
)<br />
H(t) = 50 − 50 cos<br />
12 (t − 7) .<br />
All these <strong>functions</strong> have the same values, the same amplitudes, and the same periods.<br />
Example 3: phases of the moon<br />
0 29.5<br />
Figure <strong>10</strong>.8: Periodic moon phases<br />
A cycle of waxing and waning moon takes 29.5 days approximately. Construct a periodic function<br />
to describe the changing phases, starting with a “new moon” (totally dark) and ending one cycle<br />
later.<br />
Solution:<br />
The period of the cycle is T = 29.5 days, so<br />
ω = 2π<br />
T = 2π<br />
29.5 .<br />
v.2005.1 - September 4, 2009 <strong>10</strong>