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Astr 8000 – Problem Set #3 – Due March 26, 2009 1. The equation ...

Astr 8000 – Problem Set #3 – Due March 26, 2009 1. The equation ...

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<strong>Astr</strong> <strong>8000</strong> <strong>–</strong> <strong>Problem</strong> <strong>Set</strong> <strong>#3</strong> <strong>–</strong> <strong>Due</strong> <strong>March</strong> <strong>26</strong>, <strong>2009</strong><br />

<strong>1.</strong> <strong>The</strong> <strong>equation</strong> of hydrostatic equilibrium is<br />

dp<br />

dz = −ρg<br />

where the pressure derivative with respect to height z in a stellar atmosphere depends<br />

on density ρ and gravitational acceleration g. In hot stars, the pressure is the sum of<br />

gas pressure p g and radiation pressure p R which is given by<br />

∫<br />

p R = (4π/c)<br />

K ν dν<br />

where K ν is the second moment of the intensity field. <strong>The</strong> depth variation of K ν can<br />

be obtained from the first moment of the transfer <strong>equation</strong>,<br />

dK ν<br />

dz = −χ νH ν<br />

where H ν is the Eddington flux (first moment of the intensity field).<br />

(a) Show that by changing the height variable to column mass dm = −ρ dz, the<br />

<strong>equation</strong> of hydrostatic equilibrium can be written as<br />

or<br />

∫<br />

dp g /dm = g − (4π/c) (χ ν /ρ)H ν dν<br />

dp g /dm = g(1 − Γ)<br />

where Γ is the ratio of radiative to gravitational acceleration.<br />

(b) Suppose hot stars contain only fully ionized H and He (abundance Y). If electron<br />

scattering alone is taken to provide a lower limit on the opacity, show that<br />

χ ν /ρ = n e σ e /ρ = σ e (1 + 2Y )/(m H (1 + 4Y ))<br />

where σ e is the cross section for electron scattering and m H is the mass of hydrogen.<br />

(c) Show that<br />

Γ = σ e(1 + 2Y ) L<br />

m H (1 + 4Y ) 4πcGM<br />

where L is the luminosity, G is the gravitational constant, and M is the mass.<br />

(d) Use the following data to express Γ in terms of L/L ⊙ amd M/M ⊙ :


σ e = 6.65 × 10 −25 cm 2 electron −1 , Y = 0.1, m H = <strong>1.</strong>673 × 10 −24 g, L ⊙ = 3.85 × 10 33<br />

erg s −1 , M ⊙ = <strong>1.</strong>989 × 10 33 g, and G = 6.67<strong>26</strong> × 10 −8 cm 3 g −1 s −2 .<br />

(e) Howarth & Prinja (1989, ApJS, 69, 527) give a mass and luminosity calibration<br />

for O stars that can be fit by<br />

L/L ⊙ = 317(M/M ⊙ ) <strong>1.</strong>82 .<br />

Use this relationship with your expression for Γ to find the maximum possible<br />

stellar mass (i.e., where outward radiative acceleration equals inward gravitational<br />

acceleration). [40]<br />

2. Use the Saha ionization <strong>equation</strong> to estimate the ratio of the numbers of negative<br />

hydrogen ions to neutral hydrogen atoms in the solar atmosphere. Use the form of<br />

the Saha <strong>equation</strong> given by<br />

N j /N j+1 = n e<br />

U j (T)<br />

U j+1 (T) C I T −3/2 e χ I/(kT)<br />

where C I = 2.07 × 10 −16 in c.g.s. units. Assume that the partition functions for<br />

neutral hydrogen and the negative hydrogen ion equal 2 and 1, respectively. Further<br />

assume an electron density of 5 × 10 13 cm −3 and a temperature of 6300 ◦ K (typical<br />

values near optical depth unity). [30]<br />

3. Calculate the discrete ordinate solution to the grey atmosphere<br />

I i (τ) = 3 4 F(τ + Q + µ i +<br />

n−1 ∑<br />

α=1<br />

S = J(τ) = 3 n−1<br />

4 F(τ + Q + ∑<br />

α=1<br />

L α e −kατ<br />

1 + µ i k α<br />

)<br />

L α e −kατ )<br />

using the single Gauss quadrature results for n = 4 in Table 10.1 from Collins (1989,<br />

Fundamentals of Stellar <strong>Astr</strong>ophysics [New York: Freeman]; see next page). <strong>The</strong><br />

quadrature points are<br />

µ = [.9602899, .7966665, .5255324, .1834346]<br />

(Chandrasekhar 1960, Radiative Transfer [New York: Dover]). Make a plot of the<br />

limb darkening law for the surface intensity (I(µ) at τ = 0) for both the Eddington<br />

approximation and the discrete ordinate method. Determine the degree of radiation<br />

anisotropy<br />

(I(µ = .9602899) − I(µ = .1834346))/I(µ = .9602899)<br />

fro τ = 0, 1, 10, and 100. Plot the temperature versus depth relation, T/T eff versus<br />

log τ, between τ = 0.01 and 100 for both the Eddington approximation result and the<br />

discrete ordinate solution. [30]

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