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COMPLEX GEOMETRY Course notes

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5.3 Review<br />

Theorem 5.3.1. Let X be a compact manifold:<br />

{ (⊕<br />

k<br />

(F, P ) =<br />

Ωk X , ∆ )<br />

( d<br />

⊕ )<br />

q Ω0,q (E), ∆ ∂E<br />

if X is Riemannian,<br />

E −→ X is a holomorphic vector bundle<br />

where P is an elliptic or Laplacian-like operator. This implies that<br />

where Ker(P ) is finite dimensional.<br />

C ∞ (F ) = Ker(P )⊥○P (C ∞ (F ))<br />

Corollary 5.3.1.<br />

(1) There is an isomorphism H k ∼<br />

−→ H k dR (X, Ror C) given by α ↦→ [α], where Hk is the finite dimensional<br />

space of harmonic forms.<br />

(2) There is an isomorphism H 0,q ∼<br />

−→ H q (X, E), where H 0,q is the finite dimensional space of (0, q)-forms.<br />

Both isomorphisms depend on the chosen metric.<br />

Note that<br />

HdR k (X, R) ∼= 1<br />

Hk (X, R)<br />

∼= 2 ∼ =<br />

3<br />

Ȟ(H, R)<br />

where ∼ = 1 is given by the de Rham isomorphism, ∼ = 2 and ∼ = 3 are given by the Poincaré Lemma. Recall the<br />

Dolbeaut isomorphism:<br />

(X, E) ∼ = H 0,q (X, ∂ ∂<br />

Ωp E) ∼ = (∗) H p,q (X, Ω p E) =: H p,q (X, E) (finite dimensional),<br />

Ω p E ∼ = O(∆ p TX ∗ ⊗ E) (space of holomorphic p-forms with values in E).<br />

H p,q<br />

where (∗) comes from the isomorphism Ω p E = Ker∂ 0 (A p,0 )(E) −→ A p,1 (E)). Also,<br />

H p,q (X) = H p,q (X, C) = H q (X, Ω p X<br />

) (sheaf of holomorphic functions).<br />

It is known that ∆ = ∂∆ ∂<br />

in every Kähler manifold. Then the following theorem follows:<br />

Theorem 5.3.2. Let X be a Kähler manifold. Then<br />

H k (X, C) =<br />

⊕<br />

H p,q (X).<br />

p+q=k<br />

In other words, if [α] ∈ H k (X, C) with α harmonic, then α = ∑ p+q=k αp,q , where α p,q is the (harmonic)<br />

component of type (p, q).<br />

67

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