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Homework Problem Set 5 Solutions ( )2

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5. The Maxwell-Boltzmann distribution for speeds is<br />

12<br />

F(v) = 4π v 2<br />

3/ 2<br />

⎛⎛ m ⎞⎞<br />

⎜⎜ ⎟⎟<br />

⎝⎝ 2π k B T ⎠⎠<br />

⎛⎛<br />

exp − mv2 ⎞⎞<br />

⎜⎜<br />

⎝⎝ 2k B T<br />

⎟⎟ .<br />

⎠⎠<br />

In this equation, m is the mass of a particle, k B is the Boltzmann constant, T is<br />

temperature, and v € is the speed.<br />

velocity vector,<br />

where<br />

v x ,<br />

v y, and<br />

The most probable speed<br />

€ by € the equation €<br />

The speed v is defined to be the magnitude of the<br />

2<br />

v = v x +<br />

2 vy +<br />

2<br />

[ vz ] 1/ 2 ,<br />

v z are the components of the velocity vector.<br />

€<br />

v mp corresponding to the maximum in the distribution is given<br />

€<br />

v mp =<br />

⎛⎛<br />

⎜⎜<br />

⎝⎝<br />

2k B T<br />

m<br />

1/ 2<br />

⎞⎞<br />

⎟⎟ .<br />

⎠⎠<br />

a.) Plot the Maxwell-Boltzmann distribution function F(v) (y-axis) versus v (x-axis) for a<br />

collection of atoms at 300 € K. Assume that one mole of atoms weighs 12.0 g.<br />

b.)<br />

Using the same mass as in part (a), plot € the Maxwell-Boltzmann distribution function<br />

F(v) versus v for a collection of atoms at 1000 K. Discuss the effect of temperature<br />

on the distribution of atomic speeds.<br />

€<br />

Both questions (a) and (b) are answered below.<br />

The Maxwell-Boltzmann distribution function for the atoms at 300 K is given by<br />

⎢⎢ 0.012 kg/mol<br />

( ) = 4π v 2 ⎢⎢<br />

F v<br />

3/ 2<br />

⎡⎡<br />

⎛⎛ 1mol ⎞⎞ ⎤⎤<br />

( ) ⎜⎜<br />

⎝⎝ 6.02217 × 10 23 ⎟⎟<br />

⎠⎠<br />

⎥⎥<br />

⎥⎥<br />

⎢⎢ 2π( 1.38062 × 10 -23 JK −1 )( 300 K)<br />

⎥⎥<br />

⎢⎢<br />

⎥⎥<br />

⎣⎣<br />

⎦⎦<br />

⎧⎧<br />

⎛⎛ 1mol ⎞⎞<br />

( 0.012 kg/mol)<br />

⎜⎜<br />

⎝⎝ 6.02217 × 10<br />

× exp −<br />

23 ⎟⎟ v 2 ⎫⎫<br />

⎪⎪<br />

⎠⎠<br />

⎪⎪<br />

⎪⎪<br />

⎪⎪<br />

⎨⎨<br />

2( 1.38062 × 10 -23 JK −1 ⎬⎬<br />

⎪⎪<br />

)( 300 K)<br />

⎪⎪<br />

⎩⎩ ⎪⎪<br />

⎭⎭ ⎪⎪<br />

€<br />

F( v) = ( 8.41956 × 10 −9 v 2 ) exp{ −2.40549 × 10 −6 v 2 }.<br />

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