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FDWK_3ed_Ch05_pp262-319

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Section 5.2 Definite Integrals 279<br />

1<br />

0<br />

y<br />

y = cos x<br />

<br />

2<br />

3<br />

2<br />

Figure 5.18 Because f x cos x is<br />

nonpositive on 2, 32, the integral of<br />

f is a negative number. The area of the<br />

shaded region is the opposite of this<br />

integral,<br />

32<br />

Area cos xdx.<br />

2<br />

x<br />

If an integrable function y f x is nonpositive, the nonzero terms f c k x k in the<br />

Riemann sums for f over an interval a, b are negatives of rectangle areas. The limit of the<br />

sums, the integral of f from a to b, is therefore the negative of the area of the region<br />

between the graph of f and the x-axis (Figure 5.18).<br />

b<br />

f x dx (the area) if f x 0.<br />

a<br />

Or, turning this around,<br />

Area b<br />

f x dx when f x 0.<br />

a<br />

0<br />

y<br />

a<br />

If f(c k ) 0, f(c k )x k is an area…<br />

y f(x)<br />

b<br />

x<br />

If an integrable function y f x has both positive and negative values on an interval<br />

a, b, then the Riemann sums for f on a, b add areas of rectangles that lie above the x-axis<br />

to the negatives of areas of rectangles that lie below the x-axis, as in Figure 5.19. The resulting<br />

cancellations mean that the limiting value is a number whose magnitude is less than the<br />

total area between the curve and the x-axis. The value of the integral is the area above the<br />

x-axis minus the area below.<br />

For any integrable function,<br />

…but if f(c k ) 0, f(c k )x k is<br />

the negative of an area.<br />

Figure 5.19 An integrable function f<br />

with negative as well as positive values.<br />

b<br />

f x dx (area above the x-axis) (area below the x-axis).<br />

a<br />

Net Area<br />

Sometimes b fx dx is called the<br />

a<br />

net area of the region determined<br />

by the curve y fx and the<br />

x-axis between x a and x b.<br />

y sin x<br />

[– , ] by [–1.5, 1.5]<br />

Figure 5.20<br />

<br />

sin xdx 2. (Exploration 1)<br />

0<br />

EXPLORATION 1<br />

Finding Integrals by Signed Areas<br />

It is a fact (which we will revisit) that sin xdx 2 (Figure 5.20). With that information,<br />

what you know about integrals and areas, what you know about graph-<br />

0<br />

ing curves, and sometimes a bit of intuition, determine the values of the following<br />

integrals. Give as convincing an argument as you can for each value, based on the<br />

graph of the function.<br />

1. 2<br />

sin xdx 2. 2<br />

2<br />

sin xdx 3. sin xdx<br />

<br />

0<br />

0<br />

4. <br />

2 sin x dx 5. <br />

2 sin xdx 6. 2<br />

sin x 2 dx<br />

0<br />

7. <br />

sin udu<br />

<br />

0<br />

8. 2<br />

sin x2 dx<br />

0<br />

2<br />

9. <br />

cos xdx<br />

10. Suppose k is any positive number. Make a conjecture about k sin xdx and<br />

k<br />

support your conjecture.<br />

0

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