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FDWK_3ed_Ch05_pp262-319

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Section 5.4 Fundamental Theorem of Calculus 305<br />

Explorations<br />

71. The Sine Integral Function The sine integral function<br />

Six x<br />

sin t<br />

dt<br />

0<br />

t<br />

is one of the many useful functions in engineering that are<br />

defined as integrals. Although the notation does not show it, the<br />

function being integrated is<br />

{<br />

sin t<br />

, t 0<br />

f t t<br />

1, t 0,<br />

the continuous extension of sin tt to the origin.<br />

(a) Show that Six is an odd function of x.<br />

(b) What is the value of Si0<br />

(c) Find the values of x at which Six has a local extreme<br />

value.<br />

(d) Use NINT to graph Six.<br />

72. Cost from Marginal Cost The marginal cost of printing a<br />

poster when x posters have been printed is<br />

dc 1<br />

<br />

d x 2 x<br />

dollars. Find<br />

(a) c100 c1, the cost of printing posters 2 to 100. $9<br />

(b) c400 c100, the cost of printing posters 101 to 400. $10<br />

73. Revenue from Marginal Revenue Suppose that a<br />

company’s marginal revenue from the manufacture and sale<br />

of eggbeaters is<br />

dr<br />

2<br />

2 ,<br />

d x x 1 2<br />

where r is measured in thousands of dollars and x in thousands<br />

of units. How much money should the company expect from a<br />

production run of x 3 thousand eggbeaters To find out,<br />

integrate the marginal revenue from x 0 to x 3. $4500<br />

74. Average Daily Holding Cost Solon Container receives 450<br />

drums of plastic pellets every 30 days. The inventory function<br />

(drums on hand as a function of days) is Ix 450 x 2 2.<br />

(a) Find the average daily inventory (that is, the average value of<br />

Ix for the 30-day period). 300 drums<br />

Answers:<br />

57. (b) H is increasing on [0, 6] where H(x) = f (x) > 0.<br />

(c) H is concave up on (9, 12) where H(x) f (x) 0.<br />

(d) H(12) 12<br />

f(t) dt 0 because there is more area above the x-axis<br />

0<br />

than below for y f(x).<br />

(e) x 6 since H (6) f (6) 0 and H (6) f (6) 0.<br />

(f ) x 0 since H(x) 0 on (0, 12].<br />

58. (c) s(3) 3 f (x) dx 1 0<br />

2 (9) 9 2 units<br />

(d) s(6) f (6) 0, s(6) f(6) 0 so s has its largest value<br />

at t 6 sec.s has its largest value at t = 6 sec.<br />

(e) s(t) f(t) 0 at t 4 sec and t 7 sec.<br />

(f ) Particle is moving toward on (6, 9) and away on (0, 6) since<br />

s(6) f (t) 0 on (0, 6) and then s(6) f (t) 0 on (6, 9).<br />

(b) If the holding cost for one drum is $0.02 per day, find the<br />

average daily holding cost (that is, the per-drum holding cost<br />

times the average daily inventory). $6.00<br />

75. Suppose that f has a negative derivative for all values of x and<br />

that f 1 0. Which of the following statements must be true<br />

of the function<br />

hx x<br />

f t dt<br />

0<br />

Give reasons for your answers.<br />

(a) h is a twice-differentiable function of x.<br />

True, h(x) f(x) ⇒ h(x) f(x)<br />

(b) h and dhdx are both continuous.<br />

True, h and h are both differentiable.<br />

(c) The graph of h has a horizontal tangent at x 1.<br />

h(1) f(1) 0<br />

(d) h has a local maximum at x 1.<br />

True, h(1) f(1) 0 and h(1) 0<br />

(e) h has a local minimum at x 1.<br />

False, h(1) f(1) 0<br />

(f) The graph of h has an inflection point at x 1.<br />

False, h(1) f(1) 0<br />

(g) The graph of dhdx crosses the x-axis at x 1.<br />

True, d h<br />

f(x) 0 at x 1 and h(x) f(x) is a decreasing function.<br />

dx<br />

Extending the Ideas<br />

76. Writing to Learn If f is an odd continuous function, give a<br />

graphical argument to explain why x<br />

f t dt is even.<br />

0<br />

77. Writing to Learn If f is an even continuous function, give a<br />

graphical argument to explain why x<br />

f t dt is odd.<br />

0<br />

78. Writing to Learn Explain why we can conclude from<br />

Exercises 76 and 77 that every even continuous function is<br />

the derivative of an odd continuous function and vice versa.<br />

79. Give a convincing argument that the equation<br />

x<br />

0<br />

sin t<br />

dt 1<br />

t<br />

has exactly one solution. Give its approximate value.<br />

59. (c) s(3) 3 f (x) dx 1 (3)(6) 9 units<br />

0<br />

2<br />

(d) s(t) 0 at t 6 sec because 6 f (x) dx 0<br />

0<br />

(e) s(t) f(t) 0 at t 7 sec<br />

(f) 0 t 3: s 0, s 0 ⇒ away<br />

3 t 6: s 0, s0 ⇒ toward<br />

t 6: s 0, s0 ⇒ away<br />

76. Using area, x<br />

f(t) dt 0 f(t) dt x<br />

f(t) dt<br />

0<br />

x<br />

0<br />

77. Using area, x<br />

f(t) dt 0 f(t) dt x<br />

f(t) dt<br />

0<br />

x<br />

0<br />

78. f odd → x<br />

d<br />

f(t) dt is even, but <br />

0<br />

d<br />

x<br />

f(t) dt f(x)<br />

x 0<br />

so f is the derivative of an even function. Similarly for f even.<br />

79. x 1.0648397. lim sin t<br />

0. Not enough area<br />

t→∞ t<br />

between x-axis and sin x<br />

for x 1.0648397 to get<br />

x<br />

x<br />

sin t<br />

dt back to 1.<br />

0 t<br />

or: Si(x) doesn’t decrease enough (for x 1.0648397) to get back to 1.

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