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Galois Theory: A Study of Cyclotomic Field ... - Scripps College

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Real Subfields and Quadratic Extensions 27<br />

Thus,<br />

∏<br />

f ′ (α i ) = ∏ i − α j ) = ±D.<br />

i<br />

i≠j(α<br />

When we apply this lemma to the polynomial x 19 − 1, its derivative is<br />

19x 18 . The discriminant is given by<br />

□<br />

±D =<br />

18∏<br />

i=0<br />

19ζ i(18) = ζ N 19 19 ,<br />

where the exponent N is some integer. To determine ζ N , we note that ±D<br />

is a rational number, because x p − 1 ∈ Q[x] are rational. The reason D<br />

is rational is because it is in the splitting field K over Q. Because D was<br />

symmetrically defined, it is clearly in the fixed field <strong>of</strong> the whole <strong>Galois</strong><br />

group. That is, any Q-automorphism <strong>of</strong> K must permute the roots <strong>of</strong> f;<br />

any permutation <strong>of</strong> roots will fix D. However, the fixed field K G where G<br />

is the whole <strong>Galois</strong> group G(K/Q) is itself just Q. Thus, D is in Q. The only<br />

power <strong>of</strong> ζ which is rational is 1. So, ζ N = 1 and<br />

±D = 19 19 .<br />

The sign <strong>of</strong> the discriminant is determined to be negative by carefully<br />

comparing the definition <strong>of</strong> the derivitive and Equation 4.1. So the square<br />

root <strong>of</strong> this discriminant is δ = √ −19 19 . By definition <strong>of</strong> D, it is clear that δ<br />

in the field Q(ζ). Since the square factors can be pulled out <strong>of</strong> a square root,

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