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Econometric Analysis of Cross Section and Panel Data - Free

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188<br />

Chapter 8<br />

which has dimension G L, where L ¼ L 1 þ L 2 þþL G . Then, for each i,<br />

Zi 0 u i ¼ðz i1 u i1 ; z i2 u i2 ; ...; z iG u iG Þ 0<br />

<strong>and</strong> so EðZi 0 u iÞ¼0 reproduces the orthogonality conditions (8.13). Also,<br />

0<br />

Eðzi1 0 x 1<br />

i1Þ 0 0 0<br />

0 Eðz 0<br />

EðZi 0 X i2 x i2Þ 0 0<br />

iÞ¼<br />

. . B<br />

C<br />

@<br />

A<br />

0 0 0 EðziG 0 x iGÞ<br />

ð8:16Þ<br />

ð8:17Þ<br />

where Eðz 0 ig x igÞ is L g K g . Assumption SIV.2 requires that this matrix have full column<br />

rank, where the number <strong>of</strong> columns is K ¼ K 1 þ K 2 þþK G . A well-known<br />

result from linear algebra says that a block diagonal matrix has full column rank if<br />

<strong>and</strong> only if each block in the matrix has full column rank. In other words, Assumption<br />

SIV.2 holds in this example if <strong>and</strong> only if<br />

rank Eðz 0 ig x igÞ ¼K g ; g ¼ 1; 2; ...; G ð8:18Þ<br />

This is exactly the rank condition needed for estimating each equation by 2SLS,<br />

which we know is possible under conditions (8.13) <strong>and</strong> (8.18). Therefore, identification<br />

<strong>of</strong> the SUR system is equivalent to identification equation by equation. This<br />

reasoning assumes that the b g are unrestricted across equations. If some prior<br />

restrictions are known, then identification is more complicated, something we cover<br />

explicitly in Chapter 9.<br />

In the important special case where the same instruments, z i , can be used for every<br />

equation, we can write definition (8.15) as Z i ¼ I G n z i .<br />

8.3 Generalized Method <strong>of</strong> Moments Estimation<br />

8.3.1 A General Weighting Matrix<br />

The orthogonality conditions in Assumption SIV.1 suggest an estimation strategy.<br />

Under Assumptions SIV.1 <strong>and</strong> SIV.2, b is the unique K 1 vector solving the linear<br />

set population moment conditions<br />

E½Z 0 i ðy i X i bÞŠ ¼ 0 ð8:19Þ<br />

(That b is a solution follows from Assumption SIV.1; that it is unique follows by<br />

Assumption SIV.2.) In other words, if b is any other K 1 vector (so that at least one<br />

element <strong>of</strong> b is di¤erent from the corresponding element in b), then

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