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Econometric Analysis of Cross Section and Panel Data - Free

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16<br />

Chapter 2<br />

Example 2.1 (continued):<br />

In equation (2.2) we have<br />

qEðy j xÞ<br />

qx 1<br />

¼ b 1 ;<br />

qEðy j xÞ<br />

qx 2<br />

¼ b 2<br />

As expected, the partial e¤ects in this model are constant. In equation (2.3),<br />

qEðy j xÞ<br />

qx 1<br />

¼ b 1 ;<br />

qEðy j xÞ<br />

qx 2<br />

¼ b 2 þ 2b 3 x 2<br />

so that the partial e¤ect <strong>of</strong> x 1 is constant but the partial e¤ect <strong>of</strong> x 2 depends on the<br />

level <strong>of</strong> x 2 . In equation (2.4),<br />

qEðy j xÞ<br />

qx 1<br />

¼ b 1 þ b 3 x 2 ;<br />

qEðy j xÞ<br />

qx 2<br />

¼ b 2 þ b 3 x 1<br />

so that the partial e¤ect <strong>of</strong> x 1 depends on x 2 , <strong>and</strong> vice versa. In equation (2.5),<br />

qEðy j xÞ<br />

qx 1<br />

¼ expðÞðb 1 =x 1 Þ;<br />

qEðy j xÞ<br />

qx 2<br />

¼ expðÞb 2 ð2:7Þ<br />

where expðÞ denotes the function Eðy j xÞ in equation (2.5). In this case, the partial<br />

e¤ects <strong>of</strong> x 1 <strong>and</strong> x 2 both depend on x ¼ðx 1 ; x 2 Þ.<br />

Sometimes we are interested in a particular function <strong>of</strong> a partial e¤ect, such as an<br />

elasticity. In the determinstic case y ¼ f ðxÞ, we define the elasticity <strong>of</strong> y with respect<br />

to x j as<br />

qy<br />

qx j<br />

x j<br />

y<br />

qf ðxÞ<br />

¼ <br />

qx j<br />

x j<br />

f ðxÞ<br />

ð2:8Þ<br />

again assuming that x j is continuous. The right-h<strong>and</strong> side <strong>of</strong> equation (2.8) shows<br />

that the elasticity is a function <strong>of</strong> x. Wheny <strong>and</strong> x are r<strong>and</strong>om, it makes sense to use<br />

the right-h<strong>and</strong> side <strong>of</strong> equation (2.8), but where f ðxÞ is the conditional mean, mðxÞ.<br />

Therefore, the (partial) elasticity <strong>of</strong> Eðy j xÞ with respect to x j , holding x 1 ; ...; x j 1 ;<br />

x jþ1 ; ...; x K constant, is<br />

qEðy j xÞ<br />

qx j<br />

x j<br />

x j<br />

<br />

Eðy j xÞ ¼ qmðxÞ <br />

qx j mðxÞ :<br />

ð2:9Þ<br />

If Eðy j xÞ > 0 <strong>and</strong> x j > 0 (as is <strong>of</strong>ten the case), equation (2.9) is the same as<br />

q log½Eðy j xÞŠ<br />

q logðx j Þ<br />

ð2:10Þ

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