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Controlling a Rolling Ball On a Tilting Plane - STEM2

Controlling a Rolling Ball On a Tilting Plane - STEM2

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3 The Equation of a <strong>Plane</strong><br />

Suppose a plane has a unit normal n. Let a point on the plane be given by<br />

a vector p. Then<br />

n · p = ‖p‖ cos(θ),<br />

where θ is the angle between n and p. This is the perpendicular distance d<br />

from the origin to the plane. Therefore the equation of the plane is<br />

n · p = d,<br />

where<br />

that is<br />

p =(x, y, z).<br />

n 1 x + n 2 y + n 3 z = d.<br />

4 A Description of the Tilted <strong>Plane</strong><br />

We consider a table elevated from the floor by a distance h. That is the pivot<br />

point on the table plane is located at a distance h. This pivot point in the<br />

center of the table is supported by a column of length h. We assume here<br />

for simplicity that the pivot point is on the surface of the table, neglecting<br />

certain offsets that will be needed later. The table is tilted by two actuators.<br />

We take our coordinate system so that the xy plane is the floor, and the<br />

origin is directly below the table pivot point. An x actuator is a line segment<br />

of variable length that always lies in the y = 0 plane. It is connected to the<br />

center supporting column at a point a distance c x from the pivot point in<br />

the table plane. It is connected to the table plane at a point that is at a<br />

distance t x from the pivot point. Similarly, a y actuator always lies in the<br />

x = 0 plane. It is connected to the center supporting column at a point a<br />

distance c y from the pivot point in the table plane. It is connected to the<br />

table plane at a point that is at a distance t y from the pivot point. Let the x<br />

actuator have variable length α, andthey actuator have variable length β.<br />

5

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