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ISSN 1905-7873 © 2012 - Maejo International Journal of Science ...

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24 <strong>Maejo</strong> Int. J. Sci. Technol. <strong>2012</strong>, 6(01), 12-27<br />

Appendix I<br />

The per phase equivalent circuit <strong>of</strong> SEIG feeding induction motor load at steady state is shown<br />

in Figure 9. In the equivalent circuit, the SEIG parameters R s and X ls are stator resistance and leakage<br />

reactance respectively, R r and X lr are rotor resistance and leakage reactance respectively, and X m is the<br />

magnetising reactance. The corresponding parameters are presented with subscript m for motor load.<br />

X csh is the reactance <strong>of</strong>fered by the capacitor bank, and F and are per unit frequency and prime-mover<br />

speed respectively.<br />

jFX lr<br />

jFX m<br />

jFX ls<br />

R s<br />

-jX csh<br />

/F<br />

R sm<br />

jFX lsm<br />

jFX mm<br />

jFX lrm<br />

R rm<br />

/(F- m<br />

)<br />

R r<br />

/(F-)<br />

I s<br />

Figure 9. Per phase equivalent <strong>of</strong> SEIG feeding motor load<br />

Applying KVL on stator side loop <strong>of</strong> induction generator results in<br />

Z loop I s = 0<br />

Under steady state condition, I s cannot be zero and therefore Z loop<br />

should be zero. An<br />

optimisation problem has been formulated to obtain the unknown variables X csh and F. The objective<br />

function F n is expressed as<br />

Fn( X<br />

csh, F) abs( Zloop)<br />

The values <strong>of</strong> X csh and F should lie between the respective minimum and maximum limits:<br />

Fmn F Fmx , Xcmn Xcsh Xcmx<br />

<br />

The above optimisation problem is solved through SUMT in conjunction with the Rosenbroack<br />

method <strong>of</strong> direct search technique [23]. After the convergence, the capacitance is computed.<br />

Appendix II<br />

The induction machine model is developed in a stationary reference frame while incorporating<br />

the effects <strong>of</strong> both the main flux and cross-flux saturation. The forms <strong>of</strong> v, i, r,<br />

L<br />

and G are<br />

given as<br />

T<br />

T<br />

v v v v v i i i i i r diag r r r r<br />

qs ds qr dr ; qs ds qr dr ; <br />

L<br />

L L L L<br />

<br />

L L L L<br />

<br />

L L L L<br />

<br />

L L L L<br />

sq dq mq dq<br />

dq sq dq md<br />

mq dq rq dq<br />

dq md dq rd<br />

<br />

<br />

<br />

<br />

<br />

<br />

0 0 0 0 <br />

<br />

0 0 0 0<br />

<br />

G <br />

<br />

0 <br />

rLm 0 Lr<br />

<br />

<br />

<br />

rLm 0 Lr<br />

0 <br />

<br />

s s r r<br />

The air gap voltage <strong>of</strong> SEIG does not remain constant during loading. Therefore, the<br />

magnetising inductance is calculated by calculating the magnetising current as<br />

<br />

2 2<br />

m<br />

<br />

qs<br />

<br />

qr<br />

<br />

ds<br />

<br />

dr<br />

i i i i i<br />

The inductances in [L] are evaluated [21] as

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