Vol. 7 No 5 - Pi Mu Epsilon
Vol. 7 No 5 - Pi Mu Epsilon
Vol. 7 No 5 - Pi Mu Epsilon
You also want an ePaper? Increase the reach of your titles
YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.
THE AREA OF A TRIANGLE FORMED BY THREE LINES<br />
notation and methods familiar to students taking a first course in<br />
linear algebra.<br />
We begin by forming the coefficient matrix p of the system (2)<br />
and the matrix Q . - -<br />
-<br />
One way to determine a triangle is to<br />
specify three noncollinear points X(x, x2),<br />
y(~l, Y) and Z(z, z ) to be used as<br />
vertices (Figure 1). It is well known [~oble,<br />
Daniel, 1977, p. 2091 that the area, A, of the<br />
triangle is given by the formula:<br />
where Mi, M b and Mc in Q are cofactors of elements a bi and ci in<br />
i<br />
P. For example,<br />
where the sign is chosen to make A positive.<br />
Another way to determine a triangle is to specify three non-<br />
current lines, no two parallel<br />
We note that the condition that no two lines are parallel to each other<br />
implies that the cofactors Ma , , and Me are all non-zero. Further-<br />
3 \ 3<br />
more, with this notation, formula (3a) becomes<br />
la! a2 "31<br />
2<br />
which enclose the triangle (Figure 1). Though it is an old result<br />
[salmon, 1879, p. 32 1, it is not so well known that the area, A, of the<br />
triangle is also given by the formula<br />
Is it possible for the determinant of matrix P, detP, to equal<br />
zero If it is, there will exist a non-trivialsolution (s,,<br />
the system<br />
(5a)<br />
a1s t a2s t ass3 = 0<br />
b s t b s tb3s3=0<br />
11 22<br />
s2, 8,) to<br />
The purpose of this note is to prove the formula (3a) using<br />
If s3 # 0, then<br />
equations in (5a).<br />
s2/s3,1) is also a solution to the system of<br />
Thus all three lines of system (2) pass through the