Numerical Simulation of Three-Dimensional Viscous Flows with ...
Numerical Simulation of Three-Dimensional Viscous Flows with ...
Numerical Simulation of Three-Dimensional Viscous Flows with ...
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1336<br />
ISMAIL-ZADE et al.<br />
∂ψ<br />
Γ( x 3 = 0,<br />
x 3 = l 3 ) : ψ 1 ψ 2 0, 3 ∂ 2 ψ<br />
-------- 0, 1 ∂ 2 ψ<br />
= = = ---------- = ---------- 2<br />
= 0 .<br />
∂x 3<br />
In the case <strong>of</strong> no-slip conditions, we set the following conditions:<br />
The initial conditions for temperature, density, and viscosity are set as follows:<br />
0 0<br />
0<br />
Here, the prescribed functions T *<br />
, ρ *<br />
, and µ *<br />
define the temperature and thermally unperturbed density<br />
and viscosity at the initial moment.<br />
Equations (7)–(12), combined <strong>with</strong> the boundary and initial conditions, uniquely determine the unknown<br />
functions u 1 , u 2 , u 3 , T, ρ, and µ <strong>with</strong>in Ω at any t ≥ 0. Equations (13)–(15) (<strong>with</strong> prescribed functions T, ρ *<br />
,<br />
and µ *<br />
) do not uniquely determine ψ 1 , ψ 2 , and ψ 3 under boundary conditions <strong>of</strong> any form. This is explained<br />
by the fact that u can be expressed in terms <strong>of</strong> the corresponding vector potential y only up to the gradient<br />
<strong>of</strong> an arbitrary differentiable scalar function y, because u = curly = curl(y + ∇ϕ), which implies that<br />
u = curly 1 and u = curly 2 , where y 1 = y 2 + ∇ϕ. When a potential y satisfies these relations, the potential<br />
y + ∇ϕ, where ϕ is an arbitrary sufficiently smooth function <strong>of</strong> x ∈ Ω <strong>with</strong> a compact support in Ω, satisfies<br />
these relations as well. Since ϕ is a compactly supported function on Ω, the gradient ∇ϕ does not contribute<br />
to the boundary conditions for y. In particular, this implies that Eqs. (9)–(15), combined <strong>with</strong> the boundary<br />
and initial conditions, do not uniquely determine the unknown functions ψ 1 , ψ 2 , and ψ 3 , whereas the<br />
unknown functions T, ρ *<br />
, and µ *<br />
(and, therefore, T, ρ, and µ) are uniquely determined <strong>with</strong>in Ω at any t ≥ 0.<br />
For our purposes, any potential found by solving the equations above is suitable, because the same velocity<br />
field u is obtained.<br />
4. VARIATIONAL EQUATION OF THE PROBLEM<br />
To apply a finite element method, we replace Eqs. (13)–(15) <strong>with</strong> an equivalent variational equation. We<br />
multiply Eqs. (13)–(15) by the components ω i <strong>of</strong> a test vector function w satisfying the conditions set for<br />
the vector function y. Performing these operations and using the boundary conditions for the desired and<br />
test vector functions, we obtain the variational equation<br />
which can be compactly rewritten as<br />
COMPUTATIONAL MATHEMATICS AND MATHEMATICAL PHYSICS Vol. 41 No. 9 2001<br />
∂x 3<br />
2<br />
∂x 3<br />
2<br />
∂ψ<br />
Γ( x 1 = 0,<br />
x 1 = l 1 ) : ψ 1 ψ 2 ψ 3 0, 2 ∂ψ<br />
= = = -------- = -------- 3<br />
= 0 ,<br />
∂x 1 ∂x 1<br />
∂ψ<br />
Γ( x 2 = 0,<br />
x 2 = l 2 ) : ψ 1 ψ 2 ψ 3 0, 1 ∂ψ<br />
= = = -------- = -------- 3<br />
= 0 ,<br />
∂x 2 ∂x 2<br />
Γ( x 3 = 0,<br />
x 3 = l 3 ) : ψ 1 = ψ 2 = ψ 3 = 0,<br />
∂ψ 1 ∂ψ<br />
-------- = -------- 2<br />
∂x 3 ∂x 3<br />
= 0 .<br />
For the temperature on the side faces on Ω, we set zero heat-flux conditions (as in a homogeneous Neumann<br />
problem). On the top and bottom faces <strong>of</strong> Ω, the following conditions for temperature are prescribed<br />
(as in a nonhomogeneous Dirichlet problem):<br />
Γ( x 1 = 0,<br />
x 1 = l 1 ) : ∂T/∂x 1 = 0, t ≥ 0,<br />
Γ( x 2 = 0,<br />
x 2 = l 2 ) : ∂T/∂x 2 = 0, t ≥ 0,<br />
Γ( x 3 = 0) : T( t, x 1 , x 2 , 0) = T 1 ( t, x 1 , x 2 ), t ≥ 0,<br />
Γ( x 3 = l 3 ) : T( t, x 1 , x 2 , l 3 ) = T 2 ( t, x 1 , x 2 ), t ≥ 0.<br />
T( 0,<br />
x) = T 0 *<br />
(), x ρ *<br />
( 0,<br />
x) = ρ 0 *<br />
(), x µ *<br />
( 0,<br />
x) = µ 0 *<br />
(), x x ∈ Ω.<br />
∫µ ( 2e 11 ẽ + 11 2e 22 ẽ + 22 2e 33 ẽ + 33 e 12 ẽ + 12 e 13 ẽ + 13 e 23 ẽ ) dx<br />
23 = – La∫ρω 3 dx,<br />
Ω<br />
E( yw , ) = L( w) for any admissible ω = ( ω 1 , ω 2 , ω 3 ).<br />
Ω<br />
(17)