10.02.2015 Views

Econometrics II Problem Set 8 44709 – Group 2 (SOLUTIONS)

Econometrics II Problem Set 8 44709 – Group 2 (SOLUTIONS)

Econometrics II Problem Set 8 44709 – Group 2 (SOLUTIONS)

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

<strong>Econometrics</strong> <strong>II</strong><br />

Graduate School of Management and Economics<br />

<strong>Problem</strong> <strong>Set</strong> 8<br />

<strong>44709</strong> – <strong>Group</strong> 2 (<strong>SOLUTIONS</strong>)<br />

1. a) Iterating forward:<br />

Sharif University of Technology<br />

1 <br />

1 2 <br />

<br />

<br />

The solution for can be written as:<br />

<br />

<br />

<br />

<br />

Taking the expectation, the forecast function is:<br />

<br />

The mean change in y t is always the constant 1, is reflected in the forecast<br />

function. This is a random-walk plus drift model with drift term equal to 1.<br />

<br />

b) <br />

Using the same technique as in “a)”<br />

1 23 <br />

The solution for y t+s can be written as:<br />

1 2 <br />

Page 1


The forecast function is:<br />

1 2 <br />

1<br />

2<br />

Note that the change in y t is positively related to t. As such, the slope of the<br />

forecast function is positively related to t.<br />

c) Given initial conditions for all stochastic terms:<br />

In period zero, the value of is given by: 0.5 (assume that μ 0 ,<br />

η 0 and η -1 are known) so that we can write the model as:<br />

0.5 0.5 <br />

The solution for y t+s can be written as:<br />

<br />

<br />

0.5 0.5 <br />

Hence, the forecast function is:<br />

0.5 0.5 1<br />

0.5 1<br />

Here y t is a random-walk plus a stationary component that is a MA(1) process.<br />

<br />

<br />

Page 2


d) write as: Δy t = t + ε t . Now, simply detrend the Δy t sequence<br />

to obtain a stationary sequence.<br />

e) The model has an ARIMA(0,1,2) representation.<br />

Recall that: 0.5 where . Differencing once<br />

yields: 1 0.5 0.5 where is stationary.<br />

The { } sequence is stationary as:<br />

0,<br />

1.5 , and all autocorrelations are constant.<br />

The first order autocorrelation of is:<br />

, <br />

<br />

0.25 <br />

1.5<br />

<br />

The second order autocorrelation of is:<br />

, <br />

<br />

0.5 <br />

1.5<br />

<br />

The third order autocorrelation of is:<br />

, <br />

<br />

0<br />

1.5 0<br />

<br />

and: 0.<br />

Thus, the autocorrelation function of has the same characteristics as an MA(2)<br />

process, hence, has an ARIMA(0,1,2) representation.<br />

Page 3

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!