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Concentration of Solutions

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Name Class Date<br />

Problem Solving continued<br />

Sample Problem 4<br />

Determine the molal concentration <strong>of</strong> a solution containing 81.3 g <strong>of</strong><br />

ethylene glycol, HOCH 2 CH 2 OH, dissolved in 166 g <strong>of</strong> water.<br />

Solution<br />

ANALYZE<br />

What is given in the problem?<br />

What are you asked to find?<br />

the mass <strong>of</strong> ethylene glycol dissolved, and the<br />

mass <strong>of</strong> the solvent, water<br />

the molal concentration <strong>of</strong> the solution<br />

Items<br />

Mass <strong>of</strong> solute<br />

Molar mass <strong>of</strong> solute<br />

Moles <strong>of</strong> solute<br />

Mass <strong>of</strong> solvent<br />

<strong>Concentration</strong> (molality)<br />

Data<br />

81.3 g ethylene glycol<br />

62.08 g/mol ethylene glycol<br />

? mol ethylene glycol<br />

166 g H 2 O<br />

? m<br />

PLAN<br />

What steps are needed to calculate the molal concentration <strong>of</strong> the ethylene glycol<br />

solution?<br />

Determine the amount <strong>of</strong> solute in moles and the mass <strong>of</strong> solvent in kilograms;<br />

calculate the moles <strong>of</strong> solute per kilogram <strong>of</strong> solvent.<br />

1<br />

Mass <strong>of</strong> C 2<br />

H 6<br />

O 2<br />

in g<br />

multiply by the<br />

inverted molar<br />

mass <strong>of</strong> C 2<br />

H 6<br />

O 2<br />

2<br />

Amount <strong>of</strong> C 2<br />

H 6<br />

O 2<br />

in mol<br />

moles C 2<br />

H 6<br />

O<br />

m <br />

2<br />

kg H 2<br />

O<br />

5<br />

Molality <strong>of</strong> C 2<br />

H 6<br />

O 2<br />

solution<br />

3<br />

Mass <strong>of</strong> H 2<br />

O in g<br />

multiply by the<br />

conversion factor<br />

1 kg<br />

1000 g<br />

4<br />

Mass <strong>of</strong> H 2<br />

O in kg<br />

1<br />

molar mass <strong>of</strong> C 2<br />

H 6<br />

O 2<br />

given 1 mol C 2<br />

H 6<br />

O 2 mol C2 H 6<br />

O 2<br />

g C 2<br />

H 6<br />

O 2<br />

62.08 g C2 H 6<br />

O 2<br />

given 1 kg<br />

g H 2<br />

O kg H2 O<br />

1000 g<br />

calculated above<br />

mol C 2<br />

H 6<br />

O 2<br />

m C 2<br />

H 6<br />

O 2<br />

solution<br />

kg H 2<br />

O<br />

calculated above<br />

Copyright © by Holt, Rinehart and Winston. All rights reserved.<br />

Holt ChemFile: Problem-Solving Workbook 207 <strong>Concentration</strong> <strong>of</strong> <strong>Solutions</strong>s

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