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Math 31: Chapter 8 Notes

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<strong>Math</strong> <strong>31</strong>: <strong>Chapter</strong> 8 <strong>Notes</strong><br />

8.1 Functions of Several Variables<br />

Each function we have seen so far is of the form f(x)...we “plug in” one value of<br />

the independent variable x and the function gives us one number in return. We<br />

now look at functions of the form f(x, y, z, ....) that have two or more independent<br />

variables. The function will still give us just one number in return.<br />

Examples. Consider the function of two variables f(x, y) = x 2 + y.<br />

(a) f(1, 2) =<br />

(b) f(−2, 3) =<br />

(c) f(0, 0) =<br />

Observation. Recall that f(x) = mx + b where m and b are constants is a linear<br />

function. We now look at what linear functions are in several variables...<br />

Definition. A linear function of the variables x 1 , . . . , x n is a function<br />

f(x 1 , x 2 , . . . , x n ) = a 0 + a 1 x 1 + a 2 x 2 + · · · a n x n .<br />

Examples. Here are some examples of linear functions (notice there are no powers<br />

on any of the variables.)<br />

f(x, y) = 1 − x − y f(x, y) = 3x − 2 7 y − 1<br />

f(u, w) = u+4w<br />

5<br />

f(i, j, k) = 2i + j − k − 7<br />

Observation. The notion of slope has been a bit obscured since we have multiple<br />

independent variables. However the coefficients of each variable tells us something<br />

similar to what slope tells us as we see in the next example:<br />

1


Example. Let f(x, y) = 2 + 6x − 9y.<br />

Example. Suppose the daily fixed cost for manufacturing cars and trucks at a plant<br />

is $100 thousand . It costs $8 thousand to produce each truck and $6 thousand for<br />

each car. Find the linear daily cost function C(x, y) for this plant.<br />

Definition. If we add to a linear function a term of the form bx i x j with b ≠ 0 and<br />

i ≠ j we get a second-order interaction equation.<br />

Class Exercise. ($8.1 #12)<br />

Example. The table gives the values of a function f(x, y).<br />

(a) Find f(0, 1)<br />

(b) f(2, 3) =<br />

(c) Is f linear?<br />

(d) Find an equation for f(x, y).<br />

Class Exercise. (#8)<br />

0 1 2 3<br />

0 -1 0 1 2<br />

1 3 4 5 6<br />

2 7 8 9 10<br />

3 11 12 13 14<br />

2


8.2 Three-Dimensional Space and Graphs of Functions of<br />

Two Variables<br />

Graphs of functions of two variables f(x, y) lie in three-dimensional space (3-<br />

space).<br />

Plotting points in 3-space:<br />

The familiar xy-plane has two axes, the x-axis and the y-axis. To form 3-space we<br />

form another axis called the z-axis. A point in 3-space is specified by (x, y, z) and<br />

we get to this point by going x units along the x-axis, y units along the y-axis, and<br />

z units along the z-axis.<br />

Example. Plot the points (1, 2, 3) and (−1, −2, 1).<br />

Definition. The graph of a function of two variables z = f(x, y) is the set of<br />

all points (x, y, f(x, y)) in 3-space. ( Of course, (x, y) must lie in the domain of f.)<br />

Such a graph is often called a surface.<br />

Example.<br />

(a) Sketch the graph of z = 0 and z = 1 in 3-space.<br />

(b) Sketch the graph of x = 0 and x = 1 in 3-space.<br />

3


Example. Sketch the graph of the function z = f(x, y) = x 2 + y 2 .<br />

Definition. If we have a surface z = f(x, y), and we fix a value for z, say z = c,<br />

the set of all points satisfying c = f(x, y) is a level curve of the surface.<br />

Graphs of Linear Functions: Planes The graphs of all linear functions are<br />

planes. Looking at the graphs of z = 0 and z = 1 we get a clear picture of what<br />

planes look like. For a general linear function the plane will be at some angle.<br />

Example. Sketch z = f(x, y) = 1 − x − y.<br />

(a) x-intercept (set y = z = 0):<br />

(b) y-intercept (set x = z = 0):<br />

(c) z-intercept (set x = y = 0):<br />

Three points are enough to determine a plane. We can form a triangle from these<br />

3 points. The plane of this triangle is the graph of f.<br />

Alpha demonstration:<br />

Class Exercise. ($8.2 #11-18)<br />

4


8.3 Partial Derivatives<br />

Recall. df<br />

dx<br />

is the derivative of f with respect to x. It tells us how fast is f changing<br />

as x changes.<br />

Definition. Let f(x, y, . . . ) be a function of several variables. The partial derivative<br />

of f with respect to x is the derivative we get when we differentiate<br />

f(x, y, . . . ) with respect to x while treating all other variables as constants. The<br />

partial derivative of f with respect to x is denoted by ∂f<br />

∂x<br />

partial derivatives with respect to other variable, ∂f<br />

∂y , ∂f<br />

. We can similarly define<br />

∂z , etc.<br />

Notation.<br />

• The symbol ∂f ∣<br />

∂x (a,b)<br />

means we evaluate the function ∂f<br />

∂x<br />

at the point (a, b).<br />

• ∂f<br />

∂x<br />

and<br />

∂f<br />

∂y are also denoted by f x and f y .<br />

Examples. Let f(x, y) = x 2 − 4xy.<br />

(a) ∂f<br />

∂x =<br />

(b) ∂f ∣<br />

(1,1)<br />

=<br />

∂x<br />

(c) ∂f<br />

∂y =<br />

(d) If C(x, y) is a cost function, ∂C<br />

∂x<br />

and<br />

∂C<br />

∂y<br />

are the marginal cost functions.<br />

Class Exercise. ($8.3 #46) Interpret your answer.<br />

Interpretation of Partial Derivatives and Marginal Costs:<br />

The partial derivative ∂C ∣<br />

∂x (a,b)<br />

is the approx. cost of the (a + 1) st “x” item, and<br />

∣<br />

(a,b)<br />

is the approx. cost of the (b + 1) st “y” item.<br />

∂C<br />

∂y<br />

5


Geometric Interpretation of Partial Derivatives:<br />

∂f ∣<br />

∂x (a,b)<br />

is the slope of the tangent line to the surface z = f(x, y) in the vertical<br />

plane y = b, and ∂f ∣<br />

∂y (a,b)<br />

is the slope of the tangent line to the surface z = f(x, y)<br />

in the vertical plane x = a.<br />

Second-Order Partial Derivatives: These will be helpful when we study how<br />

to maximize and minimize functions of two variables.<br />

• f xx = (f x ) x = ∂2 f<br />

∂x 2<br />

= ∂<br />

∂x (∂f ∂x )<br />

• f yy = (f y ) y = ∂2 f<br />

∂y 2<br />

= ∂ ∂y (∂f ∂y )<br />

• f xy = (f x ) y = ∂2 f<br />

∂y∂x = ∂ ∂y (∂f ∂x )<br />

• f yx = (f y ) x = ∂2 f<br />

∂x∂y = ∂<br />

∂x (∂f ∂y )<br />

Fact. Amazingly, we always have f xy = f yx !<br />

Class Exercises. As you compute these, verify that f xy = f yx .<br />

(a) ($8.3 #24)<br />

(b) ($8.3 #26)<br />

6


8.4 Maxima and Minima (2 Lectures )<br />

Day 1 : Types of Max/Min and Critical Points<br />

Definition. Let f(x, y, . . . ) be a function of several variables.<br />

• f has a relative maximum at the point (r, s, . . . ) if the value f(r, s, . . . ) is<br />

bigger than all other values in the immediate vicinity.<br />

• f has a relative minimum at the point (r, s, . . . ) if the value f(r, s, . . . ) is<br />

smaller than all other values in the immediate vicinity.<br />

• f has a absolute maximum at the point (r, s, . . . ) if the value f(r, s, . . . )<br />

is the largest value of the function over its entire domain.<br />

• f has a absolute minimum at the point (r, s, . . . ) if the value f(r, s, . . . ) is<br />

the smallest value of the function over its entire domain.<br />

Definition. Relative maxima and relative minima are called the relative extrema<br />

of f<br />

Observation. Absolute maxima and absolute minima are special kinds of relative<br />

extrema.<br />

All the above definitions have analogous notions in the single variable case. The<br />

next notion is not analogous to anything in the single variable case:<br />

Definition. Let f(x, y) be a function of two variables. f has a saddle point at<br />

(r, s) if f has a relative maximum along some slice through the point, and a relative<br />

minimum along some other slice through the point.<br />

Candidates for Extrema: Critical Points<br />

Definition. Points in the domain of f where all partial derivatives are zero are<br />

critical points of f.<br />

Fact. Critical points of f are the only candidates for relative extrema and saddle<br />

points of f in the interior of the domain of f.<br />

7


Warning. A critical point is not necessarily an extrema or saddle point! Further<br />

checks are needed to determine whether it is or not.<br />

Next lecture we will learn a test to determine if a critical point gives an extrema<br />

or not.<br />

Example. ($8.4 #14) Find all critical points of the function g(x, y) = x 2 + x +<br />

y 2 − y − 1.<br />

Class Exercise. ($8.4 #28) Find all critical points of the function g(x, y) = x 3 +<br />

y 3 + 3<br />

xy . 8


8.4 Maxima and Minima - Day 2<br />

GOAL: Classify Critical Points<br />

Definition. Let f be a function of two variables and (a, b) be a critical point. The<br />

quantity<br />

H = H(a, b) = f xx (a, b)f yy (a, b) − [f xy (a, b)] 2<br />

is called the Hessian at the point (a, b).<br />

Fact. (Second Derivative Test) Let f be a function of two variables and (a, b)<br />

be a critical point.<br />

1. If H(a, b) > 0, then,<br />

• f has a relative min at (a, b) if f xx (a, b) > 0<br />

• f has a relative max at (a, b) if f xx (a, b) < 0,<br />

2. If H(a, b) < 0,<br />

• f has a saddle point at (a, b).<br />

3. If H(a, b) = 0,<br />

• The test is inconclusive. A table or graph can be used to decide what<br />

kind of extrema exist at (a, b).<br />

Example. ($8.4 #12) Find and classify all the critical points of f(x, y) = 4−(x 2 +<br />

y 2 ).<br />

9


Class Exercise. ($8.4 #20) Find and classify all the critical points of t(x, y) =<br />

x 3 − 3xy + y 3 .<br />

Example. Find and classify all the critical points of f(x, y) = y 2 .<br />

Example. Find and classify all the critical points of f(x, y) = x 3 .<br />

10


8.5 Constrained Maxima and Minima<br />

We have seen how to find extrema of functions over their entire domains.<br />

GOAL: Find Max and Mins of a function f subject to constraints (over<br />

restricted domain)<br />

Example. If you want to make a closed box with square bases that holds 125 cm 3 ,<br />

what box dimensions produce a box requiring the least material?<br />

Example. Find the maximum value of the function f(x, y, z) = 4 − (x 2 + y 2 + z 2 )<br />

subject to the constraint (a) z = 2x and (b) z = 1.<br />

Idea: Solve the constraint for one of the variables and substitute. Then<br />

maximize the resulting function of two variables.<br />

Example. If you want to make an open-top rectangular box that will hold 4 cm 3 ,<br />

what box dimensions produce a box requiring the least material?<br />

Class Exercise. ($8.5 #6)<br />

11


Example. ($5.2 #20)<br />

Preview of Next Lecture: Sometimes it is too hard or impossible to eliminate<br />

one of the variables. For example, imagine if the constraint equation was x 2 +y 2 = 1<br />

or (zxy) 3 = x 7 + y 8 − z 9 . In such cases we can use the method of Lagrange Multipliers.<br />

We will discuss this method next lecture. Even if it is possible to solve<br />

for one of the variables, Lagrange multipliers always provides an alternative way<br />

to find extrema and can sometimes be quicker.<br />

Distance functions: The distance between two point P (x 1 , y 1 ) and Q(x 2 , y 2 ) in<br />

the xy−plane is<br />

d = √ (x 2 − x 1 ) 2 + (y 2 − y 1 ) 2<br />

.<br />

For two points in 3-space P (x 1 , y 1 , z 1 ) and Q(x 2 , y 2 , z 2 ) the distance between<br />

them is<br />

d = √ (x 2 − x 1 ) 2 + (y 2 − y 1 ) 2 + (z 2 − z 1 ) 2<br />

.<br />

Example. Find the distance between the points (3, −2) and (−1, 1).<br />

Example. Find the distance between the points (1, 1, 1) and (−1, 1, 2).<br />

Fact. The equation for a circle of radius r with center at the origin is<br />

x 2 + y 2 = r 2 .<br />

Question. What geometric shape in 3-space is given by the solutions to the equation<br />

x 2 + y 2 + z 2 = r 2 ?<br />

12


Constrained Maxima and Minima - Day 2<br />

Lagrange Multipliers<br />

Fact. Locating Relative Extrema with Lagrange Multipliers<br />

The candidates for relative extrema of f(x, y, . . . ) subject to the constraint g(x, y, . . . ) =<br />

0 are the solutions to equations<br />

f x = λg x<br />

f y = λg y<br />

· · ·<br />

g = 0<br />

The constant λ is called a Lagrange multiplier.<br />

Observation. The value of the Lagrange multiplier λ does not matter; hence, it<br />

is usually a good idea to try to eliminate it from the system of equations as early<br />

as possible.<br />

Example. Maximize f(x, y) = xy subject to the constraint x 2 + y 2 = 2.<br />

Warning. If we assume extrema exist there is no problem with just evaluating at<br />

critical points and comparing, but be aware that we are making an assumption<br />

here.<br />

Class Exercise. ($8.5 #12) Minimize f(x, y) = x 2 + y 2 subject to constraint<br />

xy 2 = 16.<br />

13


Example. ($8.5 #22)<br />

Example. ($8.5 #28) Find point on plane 2x − 2y − z + 1 = 0 closest to (1, 1, 0).<br />

14

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