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Decomposition Analysis of an Automotive Powertrain Design ...

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NLP PROBLEM<br />

FDT<br />

Objective<br />

Constraints<br />

Bounds<br />

Expressions x 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8<br />

f 1 0.4 x 1<br />

0.67<br />

x 7<br />

-0.67 f 1 1 1<br />

f 2 0.4 x 2 0.67 x 8<br />

-0.67 f 2 1 1<br />

f 3 10 - x 1 f 3 1<br />

f 4 x 2 f 4 1<br />

g 1 0.1 x 1 + 0.0588 x 5 x 7 -1.0 g 1 1 1 1<br />

g 2 0.1 x 1 + 0.1 x 2 + 0.0588 x 6 x 8 - 1.0 g 2 1 1 1 1<br />

g 3 4x 3 x 5<br />

-1<br />

+2x 3<br />

-0.71<br />

x 5 -1 + 0.0588 x 3 -1.3 x 7 -1.0 g 3 1 1 1<br />

g 4 -1<br />

4x 4 x 6 + 2x4<br />

-0.71<br />

x 6<br />

-1 + 0.0588 x -1.3 4 x 8 -1.0 g 4 1 1 1<br />

g i+4 - 0.1 - x i , i = 1, ..., 8<br />

g i+12 x i - 10, i = 1, ..., 8<br />

PARTITIONS<br />

PARTITIONED FDT<br />

x 1 x 2 x 4 x 6 x 8 x 3 x 5 x 7<br />

DP y y = (x 1 ); f(y) = (f 3 ); g(y) = (g 5 , g 13 )<br />

f 3 1<br />

DP 1 x 1 = (x 2 , x 4 , x 6 , x 8 ); f 1 (y,x 1 ) = (); f 1 (x 1 ) = f 2 + f 4<br />

f 2 1 1<br />

g 1 (y,x 1 ) = (g 2 )<br />

f 4 1<br />

g 1 (x 1 ) = (g 4 )<br />

g 2 1 1 1 1<br />

g b (x 1 ) = (g 6 , g 8 , g 10 , g 12, g 14 , g 16 , g 18 , g 20 )<br />

g 4 1 1 1<br />

DP 2 x 2 = (x 3 , x 5 , x 7 ); f 2 (y,x 2 ) = (f 1 ); f 2 (x 2 ) = ()<br />

f 1 1 1<br />

g 2 (y,x 2 ) = (g 1 ); g 2 (x 2 ) = (g 3 )<br />

g 1 1 1 1<br />

g b (x 2 ) = (g 7 , g 9 , g 11 , g 15 , g 17 , g 19 )<br />

g 3 1 1 1<br />

Figure 2. Partitioning example <strong>of</strong> <strong>an</strong> NLP problem.

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