Strength of Materials Design of steel beam under high temperature.
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Poznan University <strong>of</strong> Technology<br />
Institute <strong>of</strong> Structural Engineering<br />
<strong>Strength</strong> <strong>of</strong> <strong>Materials</strong><br />
<strong>Design</strong> <strong>of</strong> <strong>steel</strong> <strong>beam</strong> <strong>under</strong><br />
<strong>high</strong> <strong>temperature</strong>.<br />
Jakub Turbakiewicz, SE<br />
2014/2015
I. Task information<br />
The lowest, right sided <strong>beam</strong> was selected for calculations:<br />
-length <strong>of</strong> the <strong>beam</strong>: 6.5 m<br />
-type <strong>of</strong> the <strong>beam</strong>: simply supported <strong>beam</strong><br />
Assumed <strong>steel</strong>: S355:<br />
-yield strength: f y = 355 MPa<br />
-modulus <strong>of</strong> elasticity: E = 210 GPa<br />
-shear modulus: G = 81 GPa<br />
-Poisson’s ratio in elastic stage: ν = 0,3<br />
Figure 1. Frame scheme<br />
-co-efficient <strong>of</strong> linear thermal expansion: α = 1,2 ∙ 10 −5 1<br />
°C<br />
for T < 100°C<br />
II.<br />
Chosen cross-section:<br />
IPE 550 was chosen:<br />
h = 550 mm I y = 67120 cm 4<br />
b f = 210 mm I z = 2668 cm 4<br />
t f = 17,2 mm W el,y = 2440 cm 3<br />
t w = 11,1 mm W pl,y = 2787 cm 3<br />
r = 24 mm I ω = 1884000 cm 6<br />
A = 134,0 cm 2 I t = 123 cm 4<br />
m = 106 kg/m<br />
Figure 2. Cross-section scheme
Cross-section class:<br />
ε = √ 235<br />
f y<br />
= √ 235<br />
355 = 0,814<br />
-web<br />
-flange<br />
c<br />
t = h − 2 ∙ (t f + r) 550 − 2 ∙ (17,2 + 24)<br />
= = 42,13<br />
t w 11,1<br />
42,13 < 72ε<br />
42,13 < 58,32 → class 1<br />
c<br />
t = 0,5 ∙ (b f − t w − r) 0,5 ∙ (210 − 11,1 − 24)<br />
= = 5,08<br />
t f 17,2<br />
5,08 < 9ε<br />
5,08 < 7,29 → class 1<br />
The whole cross-section if a class 1 cross-section.<br />
III.<br />
<strong>Design</strong> in ambient <strong>temperature</strong><br />
Characteristic loading:<br />
-dead load: <strong>beam</strong> weight,<br />
-dead load: ceiling dead load (3,5 kN/m 2 , with frame spacing <strong>of</strong> 6,2 m equal to 21,7 kN/m),<br />
-live load (2,0 kN/m 2 , with frame spacing <strong>of</strong> 6,2 m equal to 12,4 kN/m).<br />
Figure 3. Beam loading scheme<br />
Figure 4. Moments in the designed <strong>beam</strong> - ULS loading combination<br />
Figure 5. Moments in the designed <strong>beam</strong> - SLS loading combination
Beam capacity due to bending:<br />
W pl,y = 2787 cm 3<br />
M c,Rd = W pl ∙ f y 2787 ∙ 35,5<br />
= = 98938 kNcm = 989,38 kNm<br />
γ M0 1,0<br />
M Ed<br />
≤ 1,0 → 258,40 = 0,261 < 1,0 → conditions met<br />
M c,Rd 989,38<br />
Beam capacity due to shear force:<br />
h w<br />
t w<br />
< 72 ∗ ε η<br />
h w<br />
= h − 2 ∗ (t f + r) 550 − 2 ∙ (17,2 + 24)<br />
= = 42,13<br />
t w t w 11,1<br />
72 ∗ ε 0,814<br />
= 72 ∗<br />
η 1,0 = 58,32<br />
h w<br />
< 72 ∗ ε → 42,13 < 58,32 → conditions met<br />
t w η<br />
Beam capacity due to shearing stress:<br />
Figure 6. Shear force in the designed <strong>beam</strong> - ULS loading combination<br />
V Ed = 114,18 kN<br />
A w = t w ∗ (h − 2 ∗ t f ) = 1,11 ∗ (55 − 2 ∗ 1,72) = 57,23 cm 2<br />
τ Ed = V Ed<br />
= 114,18<br />
A w 57,23<br />
= 2,00<br />
kN<br />
cm 2<br />
τ Ed<br />
f y /(√3 ∙ γ M0 ) < 1,0 → 2,00<br />
< 1,0 → 0,10 < 1,0 − conditions met<br />
35,5/(√3 ∙ 1,0)<br />
Beam capacity due to the elastic critical moment:<br />
π 2 EI z<br />
M cr = C 1<br />
(kL) 2 { √( k 2 I w<br />
) + (kL)2 GI t<br />
k w I z π 2 + (C<br />
EI 2 z g ) 2 − C 2 z g }<br />
z<br />
k = 1,0; k w = 1,0; C 1 = 1,127; C 2 = 0,454
M cr = 1,127 ∗ 3,142 ∗ 21000 ∗ 2668<br />
(1 ∗ 650) 2 ∗<br />
∗ {√( 1 1 )2 1884000<br />
2668 + (1 ∗ 650)2 ∗ 8100 ∗ 123<br />
3,14 2 ∗ 21000 ∗ 2668 + (0,454 ∗ 27,5)2 − 0,454 ∗ 27,5}<br />
= 45670,19 kNcm<br />
λ LT = √ W pl,yf y 2787 ∗ 35,5<br />
= √<br />
M cr 45670,19 = 1,472<br />
α LT = 0,34; (buckling curve b: h b > 2)<br />
Φ LT = 0,5 [1 + α LT (λ LT − 0,2) + λ 2 LT] = 0,5 ∗ [1 + 0,34 ∗ (1,472 − 0,2) + 1,472 2 ] = 1,799<br />
χ LT =<br />
1<br />
Φ LT + √ Φ 2 LT − λ 2 LT<br />
1<br />
1,0<br />
=<br />
= 0,353 ≤<br />
1,799 + √1,799 2 − 1,4722 1,472 2 = 0,46<br />
M b,Rd = χ LT ∗ W y ∗ f y 0,353 ∗ 2787 ∗ 35,5<br />
= = 34904,85 kNcm = 349,05 kNm<br />
γ M1 1,0<br />
M Ed<br />
M = 258,40 = 0,74 → as close to requested design ratio as possible<br />
b,Rd 349,05<br />
IV.<br />
<strong>Design</strong> <strong>of</strong> <strong>steel</strong> <strong>beam</strong> at <strong>high</strong> <strong>temperature</strong><br />
Figure 6. Moments in the designed <strong>beam</strong> – accidental loading combination<br />
Beam bending capacity:<br />
M fi,Ed<br />
M b,fi,t,Rd<br />
≤ 1,0<br />
M b,fi,t,Rd = χ LT,fi ∙ W pl,y ∙ k y,θ ∙ f y<br />
γ M,fi<br />
Assumed critical <strong>temperature</strong>: Θ = 550℃<br />
Max bending moment: M fi,Ed = 120,05 kNm<br />
The elastic critical moment: M cr = 34904,85 kNcm
Ambient <strong>temperature</strong> slenderness: λ LT = 1,472<br />
Reduction factors for <strong>steel</strong> parameters in <strong>high</strong> <strong>temperature</strong> (Θ = 550℃):<br />
k y,Θ = 0,625; k E,Θ = 0,455<br />
λ LT,Θ = λ LT √ k y,Θ<br />
k E,Θ<br />
= 1,472√ 0,625<br />
0,455 = 1,725<br />
α = 0,65 √ 235<br />
f y<br />
= 0,65 √ 235<br />
355 = 0,53<br />
2<br />
Φ LT,Θ = 0,5 ∗ [1 + α ∗ λ LT,Θ + λ LT,Θ ] = 0,5 ∗ [1 + 0,53 ∗ 1,725 + 1,725 2 ] = 2,445<br />
χ LT,fi =<br />
1<br />
2<br />
Φ LT,Θ + √Φ LT,Θ<br />
2<br />
− λ LT,Θ<br />
=<br />
1<br />
2,445 + √2,445 2 − 1,725 2 = 0,239<br />
The design buckling resistance moment in <strong>high</strong> <strong>temperature</strong>:<br />
M b,fi,t,Rd = χ LT,fi ∗ W y,pl ∗ k y,Θ ∗ f y<br />
γ M,fi<br />
= 148,01 kNm<br />
=<br />
0,239 ∗ 2787 ∗ 0,625 ∗ 35,5<br />
1,0<br />
= 14801 kNcm<br />
M fi,Ed<br />
= 120,05 = 0,811 = 81,1 % → Θ = 550℃ is the critical <strong>temperature</strong><br />
M b,fi,t,Rd 148,01<br />
V. Emphasizing the critical <strong>temperature</strong> and the fire resistance<br />
<strong>Design</strong> assumptions:<br />
-partial exposure<br />
-density <strong>of</strong> <strong>steel</strong>: ρ a = 7850 kg/m 3<br />
-increment <strong>of</strong> <strong>temperature</strong> rise: ∆t = 4s<br />
-heat transfer coefficient: α c = 25 W<br />
m 2 K<br />
-configuration factor: Φ = 1,0<br />
-emissivity <strong>of</strong> the <strong>steel</strong> surface: ε m = 0,7<br />
-fire emissivity: ε f = 1,0<br />
-Boltzmann’s constant: σ = 5,67 ∗ 10 −8<br />
Section factors:<br />
⌈ A m<br />
V ⌉ b<br />
= 113 1 m ; A m<br />
V = 140 1 m<br />
W<br />
m 2 K<br />
k sh = 0,9 ∙<br />
⌈ A m<br />
V<br />
⌉<br />
b<br />
A mV<br />
= 0,9 ∙ 113<br />
140 = 0,726
Temperature [°C]<br />
Functions used in MS Excel calculations<br />
Specific heat <strong>of</strong> <strong>steel</strong> for 20 0 C ≤ θ a < 600 0 C: c a = 425 + 7,73 ∙ 10 −1 ∙ θ a − 1,69 ∙ 10 −3 ∙ θ a 2 +<br />
2,22 ∙ 10 −6 ∙ θ a<br />
3 J<br />
kgK<br />
Net design heat flux: ḣ<br />
net,d = ḣ<br />
conv + ḣ<br />
rad<br />
Convection flux: ḣ<br />
conv = α c (Θ g − Θ m )<br />
Radiation heat flux: ḣ<br />
net,r = Φ ∙ ε m ∙ ε f ∙ σ ∙ [(Θ r + 273) 4 − (Θ m + 273) 4 ]<br />
Gas <strong>temperature</strong>: Θ g = 20 + 345 ∙ log 10 (8 ∙ t + 1)<br />
Temperature increase: ΔΘ a,t = k sh ∙<br />
Am<br />
V<br />
c a ∙ρ a<br />
∙ ḣ<br />
net,d ∙ Δ<br />
Results <strong>of</strong> <strong>steel</strong> <strong>temperature</strong> calculations:<br />
Air and element's <strong>temperature</strong><br />
<strong>steel</strong><br />
air<br />
900,0<br />
800,0<br />
700,0<br />
600,0<br />
500,0<br />
400,0<br />
300,0<br />
200,0<br />
100,0<br />
0,0<br />
0,0 10,0 20,0 30,0<br />
Time [min]<br />
Graph 1. Increase in <strong>steel</strong> <strong>temperature</strong> in time<br />
The critical <strong>steel</strong> <strong>temperature</strong> is reached after 816 seconds (13,6 min).
VI.<br />
Fire paint design<br />
Promapaint SC4 was chosen as fire protection paint. Three different assumptions were set:<br />
-fire resistance R15<br />
Figure 7. Fire paint specification – R15<br />
-fire resistance R30<br />
Figure 8. Fire paint specification – R30
-fire resistance R60<br />
Figure 9. Fire paint specification – R60<br />
R15 R30 R60<br />
Layer thickness [μm] 188 191 1094<br />
Amount <strong>of</strong> pain [l/m 2 ] 0,31 0,32 1,82<br />
Table 1. Fire paint specifications<br />
VII. Results<br />
Utilisation factor for<br />
normal conditions<br />
<strong>Design</strong><br />
section<br />
Critical moment in<br />
ambient temp.<br />
Med/Med,fire<br />
Critical<br />
<strong>temperature</strong><br />
Utilistaion for<br />
fire conditions<br />
Fire<br />
resistance<br />
time<br />
74 % IPE 550 349,05 kNm 2,36 550⁰C 81,1 % 816 s<br />
Table 2. Final results <strong>of</strong> the calculations