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9 FURTHER APPLICATIONS OF INTEGRATION

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SECTION 9.1<br />

ARC LENGTH<br />

6.<br />

y<br />

y<br />

2.1<br />

2<br />

2<br />

1.9<br />

0<br />

¹ 2¹<br />

x<br />

1.8<br />

3 3.1 3.2 3.3 x<br />

Notice that as x approaches π, the curve wiggles faster and faster, with decreasing amplitude. The limit as<br />

x → π does exist, and is 2. We can show that L =∞either geometrically, or by comparing the resultant<br />

∫ π<br />

dx<br />

integral to the improper integral 2<br />

0 x − π .<br />

A = 2 ∫ [ ( ) ]<br />

π<br />

1<br />

0<br />

(x − π) sin + 2 dx ≈ 17.385. (Note that this is an improper integral.)<br />

x − π<br />

Note that we can change the definition of f slightly, to “flip” the left half of the curve:<br />

⎧<br />

( ) 1<br />

⎪⎨ − (x − π) sin + 2 if x < π<br />

x − π<br />

f (x) =<br />

( ) 1<br />

⎪⎩ (x − π) sin + 2 if x > π<br />

x − π<br />

y<br />

2<br />

0<br />

¹ 2¹ x<br />

The area of this new island (“Hpela”) is now the familiar 4π, and the perimeter is still infinite.<br />

GROUP WORK 2: Cable Guy<br />

This exercise requires the students to make several assumptions. For example, when computing the length of<br />

cable needed for the sample segment shown on the left, they will have to decide which of the three figures on<br />

the right most accurately represents the cross-sectional side view of the lake bottom:<br />

10<br />

20<br />

10<br />

20<br />

10<br />

20<br />

10<br />

20<br />

Have them make an assumption and provide justification for it. Also remind students that the path of steepest<br />

485

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