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1. (15%) Sampling for defectives £rom large lots of manufactured ...

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<strong>1.</strong> (<strong>15%</strong>) <strong>Sampling</strong> <strong>for</strong> <strong>defectives</strong> £rom <strong>large</strong> <strong>lots</strong> <strong>of</strong> <strong>manufactured</strong> product yields anumber <strong>of</strong><br />

-<br />

<strong>defectives</strong>, Y, that follows a binomial probability distribution. A sampling plan consists <strong>of</strong><br />

specifying the number <strong>of</strong> items n to be included in a sample and an acceptance number "a".<br />

The <strong>lots</strong> is accepted if Y I a and rejected if Y > a. Letp denote the prop<strong>of</strong>iion <strong>of</strong><br />

<strong>defectives</strong> in the lot.<br />

(a) For n = 5 and a = 0, calculate the probability <strong>of</strong> lot acceptance if (a)p= O,.(b)p = .l,(c)<br />

p= .3,(d) p = .5,(e)p = <strong>1.</strong>0.<br />

I<br />

(b) A graph showing the probability <strong>of</strong> lot acceptace as a function <strong>of</strong> lot £radon defective is<br />

called the operating characteristic curve <strong>for</strong> the sample plan. Construct the operating<br />

characteristic curve <strong>for</strong> the plan n = 5, a = 0.<br />

2. (10%) Let m(t)=(1/6)ef+(~6)ez'+(3/6)df. Find the following:<br />

(a) E(Y)<br />

(b) V(Yr<br />

(c) The distribution <strong>of</strong> Y<br />

3. (10%) A diagnostic test <strong>for</strong> a disease is said to be 90% accurate in that if a person has the<br />

disease, the test will detect it with probability 0.9. Also, if a person does not have the disease,<br />

the test will report that he or she does not have it with probability 0.9. Only 1% <strong>of</strong> the<br />

population has the disease in question. If a person is chosen at random £rom the population<br />

and the diagnostic test indicates'that she has the disease, what is the probability that she does<br />

have the disease? Are you surprised by the answer? Would you call this diagnostic test<br />

reliable?<br />

4. (<strong>15%</strong>) Let Y, be the amount <strong>of</strong> pollutant per sample collected above the stack wifhout the<br />

cleaning device and Y, be the amount collected above the stack with the cleaner. The joint<br />

density <strong>of</strong> Y, and Y, is<br />

osy,s2, O ~ Y , ~ ~ , ~ Y , ~ Y I<br />

elsewhere.<br />

The random variable (YI -Yz) represents the amount by which the weight <strong>of</strong> pollutant can be<br />

reduce by using the cleaning device.<br />

(a) Find E(Y, -Y,).<br />

(b) FindV(Y, -Y,).


5. (20%) Let Xbe a random variable whose p.d.f.@robability density function) f is either the<br />

U(0,1), Uni<strong>for</strong>m, to be denoted byfo, or the triangular over the interval [0,1], to be denoted by<br />

fi, that is f;(x) = 4x, <strong>for</strong>0 2 x ~112; f;(x) = 4-4x, <strong>for</strong>112 2 x 2 1; and 0, otherwise.<br />

(a) Test the hypothesis Ho: f =fo v.s. HI: f =fi at level <strong>of</strong> significance a = 0.05.<br />

(b) Compute the power <strong>of</strong> the test.<br />

6. (<strong>15%</strong>) Answer the following questions:<br />

(a) A random variable Xis said to be memoryless if P{X > s+t I X > t) = P{Y > s) <strong>for</strong> all<br />

s, t <strong>1.</strong>0. Show that Xis memoryless when Xhas an exponential distribution with parameter h.<br />

(b) Let X be the interarrival time <strong>of</strong> buses at a station. IfX is exponentially distributed,<br />

describe how the memoryless property affects the waiting time <strong>of</strong> a passenger.<br />

7. (<strong>15%</strong>) After running a multiple regression analysis with five independent variables, the<br />

following ANOVA table is olitained<br />

Source<br />

Regression<br />

Residual<br />

Total<br />

d f<br />

45<br />

SS<br />

224<br />

270<br />

MS<br />

F<br />

(a) Complete the above ANOVA table.<br />

(b) Calculate R2 and adjusted R2.<br />

(c) Test the hypothesis Ho:PL=P2=P3=P4=P5=0 with a =0.05.


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TABLEIV -<br />

Values <strong>of</strong> <strong>1.</strong> df<br />

-


TABLE VII (cont.)<br />

Valuer <strong>of</strong> x:


TABLEVIII (cont)<br />

Values <strong>of</strong> Fa<br />

dfd<br />

u<br />

dfn<br />

0.10<br />

0.05<br />

25 0.025<br />

0.01<br />

0.005<br />

0.10<br />

0.05<br />

26 0.025<br />

0.01<br />

0.005<br />

0.10<br />

0.05<br />

27 0.025<br />

0.01<br />

0.005<br />

0.10<br />

0.05<br />

28 0.025<br />

0.01<br />

0.005<br />

0.10<br />

0.05<br />

29 0.025<br />

0.01<br />

0.005<br />

0.10<br />

0.05<br />

30 0.025<br />

0.01<br />

0.005<br />

0.10<br />

0.05<br />

60 0.025<br />

0.01<br />

0.005<br />

0.10<br />

0.05<br />

120 0.025<br />

0.01<br />

0.005

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