10.07.2015 Views

Thermodynamic Stability: Free Energy and ... - McGill University

Thermodynamic Stability: Free Energy and ... - McGill University

Thermodynamic Stability: Free Energy and ... - McGill University

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

<strong>Free</strong> <strong>Energy</strong> -12- Chemistry 223principle we expect that the reaction should shift to the left (i.e., less dissociation) as pressure isincreased. Our final equation for α shows this. For this reaction, as we shall see in the next section,K P (T )decreases as temperature increases, which when used with our expression for α isagain consistent with LeChatellier’s principle.5.3. Temperature Dependence of K PThe equilibrium constant, K P ,isonly a function of the temperature. From its definition,cf. Eq. (34),d ln(K P )dT=− d(∆G(0) /RT )dT=− 1 ⎛RT 2 ⎜T d(∆G(0) )−∆G (0)⎞ ⎟ = T ∆S(0) +∆G (0)=⎝dT ⎠RT 2∆H(0)RT 2 ,(39)where the second to last equality follows when Eqs. (27a) <strong>and</strong> (34) are used. This is known asthe Gibbs-Helmholtz equation. Thus, by integrating we find thatln ⎡ K P (T 2 ) ⎤⎢ ⎥ =⎣K P (T 1 ) ∫ T 2⎦(0)∆H ⎛ 1dT ≈ − 1 ⎞RT2R ⎝ T 1 T 2 ⎠ . (40)T 1∆H (0)Equation (40) follows if we assume that ∆H (0) is approximately constant with respect to temperature,or equivalently, that ∆C P ≈ 0(which also implies that ∆S (0) is constant. Why?). Indeed,with this approximation, Eq. (40) simply states thatK P (T 2 ) ⎛K P (T 1 ) = exp ⎜− ∆G(0) (T 2 )+ ∆G(0) (T 1 ) ⎞⎟, (41)⎝RT 2 RT 1 ⎠where ∆G (0) (T ) =∆H (0) − T ∆S o ,asusual. Finally, note, that as in our discussion of LeChatellier’sprinciple, the equilibrium will shift to the product side, i.e., K P increases, when the temperatureis raised if ∆H (0) >0.There is a simple graphical way in which to apply the Gibbs-Helmholtz equation. Byexpressing Eq. (39) as a differential, it follows thatd ln(K P ) =∆H(0)(0)dT =−∆HRT2Rd⎛ 1 ⎞⎝ T ⎠ ;hence, plotting ln(K P )versus 1/T will give a curve whose slope at any point is −∆H (0) /R, <strong>and</strong> tothe extent that ∆H (0) is independent of temperature, will give a straight line. This is a powerfulway todetermine enthalpy (<strong>and</strong> entropy) changes without having to do calorimetry.5.4. <strong>Free</strong> <strong>Energy</strong> <strong>and</strong> Entropy of MixingPerhaps the simplest process is one where two samples of different pure gases are isothermallymixed as depicted in the figure belowFall Term, 2014

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!